oracle数据库对test_table表的三个列count1,count2,count3求sum的两种sql,做个记录 第一种 select sum (case when count1 is not null then count1 when count2 is not null then count2 when count3 is not null then count3 else '0' end ) a from test_table 第二种 select sum(decode(count
注:本文来源于<oracle查询某张表的外键(最终解决办法)> 一:几个查询表外键的脚本 select b.table_name, b.column_name from user_constraints a inner join user_cons_columns b on a.constraint_name = b.constraint_name where a.r_constraint_name in ( select e.constraint_name from user_constra
readonly_table=False#默认表单不锁定 readonly_table=True#默认表单不锁定 # forms.py # ————————19PerfectCRM实现King_admin数据修改———————— from django import forms from crm import models # class CustomerModelForm(forms.ModelForm): # class Meta: #调用内置方法 # model = models.Cust
知道是两张表进行更新,之前作过mysql的,直接就写了: update a,b set a.code = b.code wehre a.id = b.id 然后就报错了,上网查了下知道oracle不能这样子写 之后找到如下的办法: UPDATE a set a.code = (select b.code from b where a.id = b.id) 但是这条语句如果数据多的话会很慢,因为他要每条数据都要跟新 然后又找到了这条sql: MERGE INTO a USING b ON ( a.
--察看一张表的约束select table_name,constraint_name,constraint_type from user_constraints where table_name=upper('HY_delivery_history') select table_name,constraint_name,constraint_type from dba_constraints where table_name=upper('HY_delivery_history') --察看一
1.表数据结构如下 select * from test t , 'jerry'); , 'jerry'); , 'jerry'); , 'tom'); , 'tom'); , 'jake'); , 'jake'); , 'jake'); 2.删除sql如下 a.name去重,取最小的字段 b.使用exists删除重复的数据 delete test a where not exists ( select * from (select min(id) id, name from test grou
declare t_name varchar2(100) := upper('dba_tab_columns'); cursor c_col is select column_name from dba_tab_columns where table_name = t_name order by column_id; v_sql varchar2(2000);begin v_sql := 'SELECT '; for r_col in c_col loop v_sql := v_sql || r