涉及场景 需要查出同一ID下 COLUMN_A字段为数值型的 多条数据 只去COLUMN_A为最小值的那条 SELECT * FROM (SELECT A.ID, A.COLUMN_A, ROW_NUMBER() OVER(PARTITION BY A.ID ORDER BY A.COLUMN_A) AS COUNTNUM FROM TABLE_NAME A GROUP BY A.COLUMNNAME) WHERE COUNTNUM = 1 注: 重点在于此句 ROW_NUMBER() OVER
ORACLE查出表所有的触发器及触发器详细信息 一.查all_triggers表得到trigger_name Sql代码 select trigger_name from all_triggers where table_name='XXX'; 二.根据trigger_name查询出触发器详细信息 Sql代码 select text from all_source where type='TRIGGER' AND name='TR_XXX';
转自:http://bbs.csdn.net/topics/370033478 对于Oracle中分页排序查询语句执行效率的比较分析 作者:lzgame 在工作中我们经常遇到需要在Oracle中进行分页.排序.查询的组合SQL语句,举例来说,通常我们会这样写:(假定表test中id是主键,并且id从1开始没有间断顺序排列) 1. SELECT * FROM ( SELECT id,a1,a2,a3,a4,a5,a6,a7,a8,a9, ROWNUM AS rn FROM test
如何用SQL排除重复结果只取字段最大值的记录?要求得到的结果(即是PID相同的记录只取ID值最大的那一条). select * from [Sheet1$] a from [Sheet1$] where PID=a.PID and ID>a.ID) select a.* from [Sheet1$] a inner join (select PID,max(ID) as max_id from [Sheet1$] group by PID) b on a.PID=b.PID and a.ID=b
oracle 监控执行的sql语句 select * from v$sqlarea a where module='PL/SQL Developer' order by a.FIRST_LOAD_TIME desc select * from v$sqlarea a where module='PL/SQL Developer' order by a.FIRST_LOAD_TIME desc 监视oracle的执行sql情况: select q.sql_text from v$session s