select * from student order by id drop table student select * from oracletest create table student( idcard varchar2(18), name varchar2(20), sex int, high int, age int ) insert into student values ('450326198912241844','罗江超',0,178,null);insert into st
select count(case 分数字段 when 100 then 1 end) as [满分],count(case when 分数字段 between 90 and 99 then 1 end) as[90-99分],count(case when 分数字段 between 80 and 89 then 1 end) as[80-89分],count(case when 分数字段 between 70 and 79 then 1 end) as[70-79分],count(case w
--只是加了固定日期,可以根据需求给成变量形式(BY 少年工藤) -思路:根据日期区间循环判断每一天是周日(1).周六(7)不变,其他加1 1 DECLARE @DAY DATE,@COUNT INT ' ' BEGIN SET @COUNT=@COUNT+( END ) ,@DAY) END SELECT @COUNT
public class Test_currentTimeMillis { public static void main(String[] args) { long start=System.currentTimeMillis(); for(int i=0;i<Integer.MAX_VALUE;i++){} long end=System.currentTimeMillis(); System.out.println("for语句执行时长:"+(end-start)+&quo