我们要用order by id asc得出的排序应该是,4,好了原理就这么简. sql实现方法,代码如下: : 代码如下: $sql ="Select 字段 from 表名 where id>3 order by id asc limit 1"; 得出的结果与我们想的是一样的,好了最后我把自己以前写的一个函数分享给各位,代码如下:代码如下: /* int $tag 0 int $fid*/ function nextPre($tag=0,$zid,$fid) { if( $tag
记order by 语句对null值排序: 目录 记order by 语句对null值排序: MySQL: Oracle: SqlServer: MySQL: 将null值放在最后 select * from user order by i f(isnull(sort), 1, 0),sort asc,publish_time desc; 将null值放在最前 select * from user order by if(isnull(sort), 0, 1),sort asc,publish_
ORACLE sql 排序 根据两个条件排序,根据id号由小到大排序,同时country字段是北京的排最前面前面,其次上海,..大连,最后是其他城市,怎么写? 写法如下:select * from proviceorder by (case when country='北京' then 0 when country='上海' then 1 when country='广东' then 2 when country='深圳' then 3 when country='杭州' then 4 when
This is a problem given in the Graduate Entrance Exam in 2018: Which of the following is NOT a topological order obtained from the given directed graph? Now you are supposed to write a program to test each of the options. Input Specification: Each in
/*Oracle数据库查询日期在两者之间*/ SELECT DISTINCT ATA FROM LM_FAULT WHERE ( OCCUR_DATE BETWEEN to_date( '2017-05-01', 'yyyy-MM-DD' ) AND to_date( '2017-05-15', 'yyyy-MM-DD' ) ) ORDER BY ATA DESC ; 修改如下: 不忘初心,如果您认为这篇文章有价值,认同作者的付出,可以微信二维码打赏任意金额给作者(微信号:382477247)哦
使用order by 可以对结果进行排序, 默认情况下,order by 以升序进行排序,因此ASC 子句是可选的. DESC 是降序排列. 升序 select * from emp where deptno = 10 order by sal ; 也可以写成 select * from emp where deptno = 10 order by sal asc; 降序 select * from emp where deptno = 10 order by sal desc; 不一定要自定
工作中需用到order by 后两个字段排序,但结果却产生了一个Bug,以此备录. [1]复现问题场景 为了说明问题,模拟示例数据库表students,效果同实例. 如下语句Sql_1: SELECT * FROM students st ORDER BY st.sAge, st.sGrade DESC; (1)预期结果: sAge和sGrade两个字段都按降序排列 (2)实际结果: sAge按升序排序,sGrade按降序排列 (3)分析原因: order by 多个字段时,Sql语法理解错误导