链接:https://www.luogu.org/problemnew/show/P3031 题面: 题目描述 Farmer John has lined up his N (1 <= N <= 100,000) cows in a row to measure their heights; cow i has height H_i (1 <= H_i <= 1,000,000,000) nanometers--FJ believes in precise measurements
题目如下: Stack is one of the most fundamental data structures, which is based on the principle of Last In First Out (LIFO). The basic operations include Push (inserting an element onto the top position) and Pop (deleting the top element). Now you are su
原文链接https://www.cnblogs.com/zhouzhendong/p/ARC101D.html 题目传送门 - ARC101D 题意 给定一个序列 A . 定义一个序列 A 的中位数为:给 A 排序,得到的第 $\left\lfloor\cfrac{i}{2}\right\rfloor+1$ 项的值. 序列 B 由序列 A 的所有连续子序列的中位数构成. 问序列 B 的中位数是多少. 序列中可能出现重复的数,$|A| \leq 10^5$ . 题解 注意这里说的“中位数”是题意里
Median Filter Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1092 Accepted Submission(s): 269 Problem Description Median filter is a cornerstone of modern image processing and is used extens
题意: 现在有n个物品,第i个物品他的位置在a[i],他的重量为w[i].每一个物品移动一步的代价为他的w[i].目前有2种操作: 1. x y 将第x的物品的重量改为y 2.l r 将编号在 [ l, r ]之间的所有物品移动到一起,求最小的花费是多少. 带权中位数,学习了->这里 先来考虑一下货仓选址问题,就是一堆不带权值的数,选出一个点使得所有点到他的距离之和最小,那么肯定是选中位数最优 然后加上权值限制,这玩意儿有个学名叫做带权中位数 带权中位数为满足$\sum_{i=1}^x w_i\
1057 Stack (30 分) Stack is one of the most fundamental data structures, which is based on the principle of Last In First Out (LIFO). The basic operations include Push (inserting an element onto the top position) and Pop (deleting the top element).
牛客2019多校联盟Day7 Fine the median 题意: 每次给数组插入区间[Li,Ri] 内的所有数,每操作一次查询中位数. 遇到这题真的算是巧合,然而就是这种冥冥之中的缘分,给了我线段树的一个全新的思想. 这题与以往的线段树做法有所不同,常规的线段树题目,可能就是一个点区间代表一个数据,然后找个区间最大值什么的. 这种很显而易见的,对吧?因为点区间代表了一个点,仅仅是一个点,所以做起来比较容易. 而今天这题十分有趣.它的点区间代表的是一个区间. 比如这题,我们去怎么解决呢? 对
题目链接: C. Subsequences time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output For the given sequence with n different elements find the number of increasing subsequences with k + 1 elements. It is