pascals triangle帕斯卡三角形

Pascal's Triangle(帕斯卡三角)

Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5,Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ]分析:此题其实就是表现出帕斯卡三角的特征:它是一个三角形矩阵,其顶端是 1,视为(row0).第1行(row1)(1&1)两个1,这两个1是由他们上头左右两数之和 (不在三角形内的数视为0).依此类推产

118 Pascal's Triangle 帕斯卡三角形杨辉三角形

给定 numRows, 生成帕斯卡三角形的前 numRows 行.例如, 给定 numRows = 5,返回[ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1]]详见:https://leetcode.com/problems/pascals-triangle/description/ Java实现: class Solution { public List<List<Integer>> generate(int numRo

leetcode-119-Pascal's Triangle II（生成某一行的帕斯卡三角形）

题目描述: Given a non-negative index k where k ≤ 33, return the kth index row of the Pascal's triangle. Note that the row index starts from 0. Example: Input: 3 Output: [1,3,3,1] Follow up: Could you optimize your algorithm to use only O(k) extra space

leetcode-118-Pascal's Triangle（生成具有n行的帕斯卡三角形）

题目描述: Given a non-negative integer numRows, generate the first numRows of Pascal's triangle. Example: Input: 5 Output: [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 要完成的函数: vector<vector<int>> generate(int numRows) 说明: 1.这道题目给定一个行数,要求返回具有给定行

【LeetCode-面试算法经典-Java实现】【118-Pascal's Triangle（帕斯卡三角形）】

[118-Pascal's Triangle(帕斯卡三角形(杨辉三角))] [LeetCode-面试算法经典-Java实现][全部题目文件夹索引] 原题 Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5, Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 题目大意给定一个正整数n,求n层帕斯卡三角

119 Pascal's Triangle II 帕斯卡三角形 II Pascal's Triangle II

给定一个索引 k,返回帕斯卡三角形(杨辉三角)的第 k 行.例如,给定 k = 3,则返回 [1, 3, 3, 1].注:你可以优化你的算法到 O(k) 的空间复杂度吗?详见:https://leetcode.com/problems/pascals-triangle-ii/description/ Java实现: class Solution { public List<Integer> getRow(int rowIndex) { List<Integer> res = new

LeetCode Pascal's Triangle Pascal三角形

题意:给一个数字,返回一个二维数组,包含一个三角形. 思路:n=0.1.2都是特例,特别处理.3行以上的的头尾都是1,其他都是依靠上一行的两个数.具体了解Pascal三角形原理. class Solution { public: vector<vector<int> > generate(int numRows) { vector<vector<int> > ans; if(!numRows) return ans; vector<int> tm

hdu 1451 Area in Triangle(计算几何三角形)

Given a triangle field and a rope of a certain length (Figure-1), you are required to use the rope to enclose a region within the field and make the region as large as possible. Input The input has several sets of test data. Each set is one line cont

LeetCode 120. Triangle （三角形）

Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below. For example, given the following triangle [ [], [,4], [6,,7], [4,,8,3] ] The minimum path sum from top to bottom is 11 (i.e.,

2.Triangle （三角形）

1.等腰直角三角形: https://www.cnblogs.com/FlyingLiao/p/9869040.html 2.1任意三角形: <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title></title> <style> .yuanXing{ width:60px; border-top:30px solid black; bor

120. Triangle(动态规划三角形最小路径难想)

Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below. For example, given the following triangle [ [], [,4], [6,,7], [4,,8,3] ] The minimum path sum from top to bottom is 11 (i.e.,

611. Valid Triangle Number三角形计数

［抄题］: 给定一个整数数组,在该数组中,寻找三个数,分别代表三角形三条边的长度,问,可以寻找到多少组这样的三个数来组成三角形? [暴力解法]: 全部都用for循环时间分析: 空间分析: ［思维问题］: 可以用两层循环:for循环中嵌套while,用过但是没意识［一句话思路］: ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 用线段减法可以避免扫描多余状态数组要先排序,提前注释中形成习惯［二刷］: ［三刷］: ［四

[Leetcode] pascals triangle ii 帕斯卡三角

Given an index k, return the k th row of the Pascal's triangle. For example, given k = 3,Return[1,3,3,1]. Note: Could you optimize your algorithm to use only O(k) extra space? 题意:给定整数K,返回行下标为K的数组. 思路: 关键点是,每次遍历数组时都是从后往前遍历,因为从前往后遍历,没有办法保存之前所得到的信息.若从前

LeetCode OJ：Triangle（三角形）

Given a triangle, find the minimum path sum from top to bottom. Each step you may move to adjacent numbers on the row below. For example, given the following triangle [ [], [,4], [6,,7], [4,,8,3] ] 一开始的题目的意思理解错了 ,以为是位数相差一就是临近的意思,但实际上这里意思是图形上面的那种临近,和原

D3D triangle list(三角形列) 小样例

画三角形列的样例程序 #pragma once #pragma comment(lib,"d3d9.lib") #pragma comment(lib,"d3dx9.lib") #include<d3d9.h> #include<d3dx9.h> //TODO: -1 custom vertex struct CUSTOMVERTEX { float x; float y; float z; float rhw; }; #define D3D

python3练习-杨辉三角/帕斯卡三角形

杨辉三角形式如下: 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 # 期待输出: # [1] # [1, 1] # [1, 2, 1] # [1, 3, 3, 1] # [1, 4, 6, 4, 1] # [1, 5, 10, 10, 5, 1] # [1, 6, 15, 20, 15, 6, 1] # [1, 7, 21, 35, 35, 21, 7, 1] # [1, 8, 28, 56, 70, 56, 28, 8, 1] # [1, 9, 36,

POJ 1673 EXOCENTER OF A TRIANGLE(解三角形重心)

题目链接:http://poj.org/problem?id=1673 AC代码: #include<cstdio> #include<cmath> #include<algorithm> #include<iostream> #include<cstring> using namespace std; typedef long long ll; ; const double pi = acos(-1.0); int sgn(double x)

118. Pascal's Triangle

题目: Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5, Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 代码: 仔细一看,规律就是本层第一个和最后一个的元素都是1,其他的元素分别等于上一层同位置元素加上前一个位置的元素. 一百度,才知道,这就是大名鼎鼎的杨辉三角!只可惜,在欧洲,这个表叫做帕斯

C#解leetcode:119. Pascal's Triangle II

题目是: Given an index k, return the kth row of the Pascal's triangle. For example, given k = 3,Return [1,3,3,1]. Note:Could you optimize your algorithm to use only O(k) extra space? (注意:这里要求空间为O(k)) 一个满足条件的答案如下: public class Solution { public IList<int

LeetCode——Pascal's Triangle

Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5, Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] 原题链接:https://oj.leetcode.com/problems/pascals-triangle/ 题目 :给定n,生成n行的帕斯卡三角形. 思路:帕斯卡三角形也就是杨辉三角形,依据

Pascal's Triangle leetcode

Given numRows, generate the first numRows of Pascal's triangle. For example, given numRows = 5,Return [ [1], [1,1], [1,2,1], [1,3,3,1], [1,4,6,4,1] ] Subscribe to see which companies asked this question 0 0 0[1]0 0[1 1]0 0[1 2 1]0 0[1 3 3 1]0 0[1 4 6

pascals triangle帕斯卡三角形

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