PE知识复习之PE的各种头属性解析 一丶DOS头结构体 typedef struct _IMAGE_DOS_HEADER { // DOS .EXE header WORD e_magic; // Magic number WORD e_cblp; // Bytes on last page of file WORD e_cp; // Pages in file WORD e_crlc; // Relocations WORD e_cparhdr; // Size of header in pa
LVM XFS增加硬盘分区容量(resize2fs: Bad magic number -- :: 分类: Linux LVM XFS增加硬盘分区容量(resize2fs: Bad magic number in super-block while) 给某个硬盘增加分区之后 [root@Mysql01-- ~]# df -h Filesystem Size Used Avail Use% Mounted on /dev/mapper/vg_mysql0121366-LogVol02 .7G .6
Magic Number (zoj3622) Time Limit : 4000/2000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 21 Accepted Submission(s) : 7 Problem Description A positive number y is called magic number if for every positive integer
Magic Number Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4323 Description There are many magic numbers whose lengths are less than 10. Given some queries, each contains a single number, if t
Magic Number Time Limit: 2 Seconds Memory Limit: 32768 KB A positive number y is called magic number if for every positive integer x it satisfies that put y to the right of x, which will form a new integer z, z mod y = 0. Input The input has mul
Problem H Time Limit : 4000/2000ms (Java/Other) Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 24 Accepted Submission(s) : 8 Problem Description A positive number y is called magic number if for every positive integer x it satisfi
A - Magic Number Time Limit:2000MS Memory Limit:32768KB 64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3622 Appoint description: Description A positive number y is called magic number if for every positive integer x it satisfies tha
I am trying to resize a logical volume on CentOS7 but am running into the following error: resize2fs (-Dec-) resize2fs: Bad magic number in super-block while trying to open /dev/mapper/centos-root Couldn't find valid filesystem superblock. solution:
今天在进行lvm扩容之后,按照惯例进行 resize2fs 操作,发现报如下错误: # resize2fs /dev/centos/root resize2fs 1.42.9 (28-Dec-2013) resize2fs: Bad magic number in super-block while trying to open /dev/centos/root Couldn't find valid filesystem superblock. 检查 /dev/centos/root 文件系统
Magic Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1867 Accepted Submission(s): 763 Problem Description There are many magic numbers whose lengths are less than 10. Given some queri
先上题目: Magic Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1433 Accepted Submission(s): 605 Problem Description There are many magic numbers whose lengths are less than 10. Given some
问题描述:根目录空间占用率100% 首先用传统resize2fs方式调整分区: resize2fs -p /dev/mapper/centos-home 50Gresize2fs 1.42.9 (28-Dec-2013)resize2fs: Bad magic number in super-block while trying to open /dev/mapper/centos-homeCouldn't find valid filesystem superblock. 报错原因是因为文件系
调试过debug版本的vc程序的人一定对0xCCCCCCCC和0xCDCDCDCD这样的内存很有印象.这是debug版本的CRT为了方便调试程序,在分配出来还没有初始化的时候提供的初始值. 实际上,Windows上面还有更多这样的初始值,见下表: Uninitialized BAADF00D Used by Microsoft's LocalAlloc/GlobalAlloc/HeapAlloc(LMEM_FIXED) to mark uninitialised allocated heap m
http://acm.hdu.edu.cn/showproblem.php?pid=4323 题意: 给出n个串和m次询问,每个询问给出一个串和改变次数上限,在不超过这个上限的情况下,n个串中有多少个串可以转化为询问中给的串. 思路: 明显的编辑距离DP,直接暴力过了,网上有用bk树的,可惜我不会. #include<iostream> #include<cstdio> #include<cstring> using namespace std; int n, m; ]
原文:http://www.360doc.com/content/13/0105/17/6295074_258392439.shtml 调试过debug版本的vc程序的人一定对0xCCCCCCCC和0xCDCDCDCD这样的内存很有印象.这是debug版本的CRT为了方便调试程序,在分配出来还没有初始化的时候提供的初始值. 实际上,Windows上面还有更多这样的初始值,见下表: Uninitialized BAADF00D Used by Microsoft's LocalAlloc/Glob