1.十进制转换为二进制 var toBin = (n) => { if(n == 0) return '0'; var res = ''; while(n != 0) { res = n % 2 + res n = parseInt(n / 2) } return res; } 2.二进制转换为十进制 var toDecimal = (s) => { var res = 0; var arr = s.split(''); var len = arr.length; for(var i = 0;
先上用Python写的十进制转二进制的函数代码: def Dec2Bin(dec): result = '' if dec: result = Dec2Bin(dec//2) return result + str(dec%2) else: return result print(Dec2Bin(62)) 图解此函数执行过程: 文字描述此函数的执行过程: 以十进制数10作为例子来解释递归问题.首先,进入函数Dec2Bin(10),此时参数dec=10,而result接受的是Dec2Bin(5)的
闲着没事写了个简单的十进制转二进制的算法,很简单,个人记录一下,不妥之处请指正. public static String toBinaryString(int j) { if (j < 0) { throw new NumberFormatException("不支持负数"); } double i = (double) j; StringBuilder sb = new StringBuilder(); while (true) { if (i % 2 == 0) sb.ap