一.创建获取表更新时间的函数 --获取表记录更新时间(通过表磁盘存储文件时间) create or replace function table_file_access_info( IN schemaname text, IN tablename text, OUT last_access timestamp with time zone, OUT last_change timestamp with time zone )language plpgsql AS $func$ declare t
一.问题发现 命令行进入数据库实例手动给某张表进行alter操作,发现如下报错. mysql> use xx_xxx; No connection. Trying to reconnect... Connection Current database: *** NONE *** Reading table information for completion of table and column names You can turn off this feature to get a quic
在oracle数据库中你要在程序里得到一张表的数据就必须先创建游标和SQL Service不一样. --创建游标create or replace package pkg_Dataas type refcursor is REF cursor; procedure pro_rows(refcursor out refcursor);end pkg_Data; --创建存储过程create or replace procedure prc_DataInput(dateStr in varchar2
现有6张表存在关联关系,要删除主表则其他5张表关联数据也要一块删掉(单条sql多id批量删除) delete t1,t2,t3,t4,t5,t6 FROM rmd_v AS t1 LEFT JOIN rmd_v1 AS t2 ON t1.uuid = t2.rvuuid LEFT JOIN rmd_v2 AS t3 ON t1.uuid = t3.rvuuid LEFT JOIN rmd_v3 AS t4 ON t1.uuid = t4.rvuuid LEFT JOIN rmd_v4 AS t5
有两张表A和B,要求往A里面插入一条记录的同时要向B里面也插入一条记录,向B里面插入一条记录的同时也向A插入一条记录.两张表的结构不同,需要将其中几个字段对应起来.可以用下面的触发器实现. 表A的触发器: begin set @disable=1; if @disable=1 and NOT EXISTS(SELECT 1 FROM tableB where ID=new.ID) then insert into tableB (ID,对应字段1) values(new.ID,new.对应字段1
ALTER TRIGGER [dbo].[tri_test2] ON [dbo].[student] for INSERT,DELETE,UPDATEAS BEGIN if not exists (select * from deleted) --新增 insert student2(stu_id,stu_name,stu_sex,stu_birthday,class_id) select stu_id,stu_name,stu_sex,stu_birthday,class_id from in
select a.constraint_name, a.column_name from user_cons_columns a, user_constraints b where a.constraint_name = b.constraint_name and b.constraint_type = 'P' and a.table_name = 'AA'-------大写 查看AA表的主键约束名称,以及主键约束的字段名称. 如果没有,则返回空
利用Oracle中系统自带的两个视图可以实现查看表中主键信息,语句如下:select a.constraint_name, a.column_name from user_cons_columns a, user_constraints b where a.constraint_name = b.constraint_name and b.constraint_type = 'P' and a.table_name = '大写的表名' 查看表的主键约束名称,以及主键约束的字段名称.如果没有,则返
(user 为要更改数据的表 ,set后边需要更改的内容, where后加条件) update user a,user_copy b set a.manager_introduct=b.rwjs where a.funds_manager_id=b.fund_manager_id and resource='***'
转载:https://blog.csdn.net/qq13650793239/article/details/81142134 mysql数据库中information_schema 数据库存储了数据库很多信息,可以通过查询tables表来获得所需要的表相关信息. mysql> select table_name,table_rows from tables order by table_rows desc limit 10;+--------------------+------------
今天在QQ群众讨论到一个问题,记录下下来,一边以后用的时候可以翻阅 总结除了三种方法 --方法1,,这一种方法不行,,错误的认识了,@@ROWCOUNT,,,唉,,学艺不精,,丢人啊 SELECT TOP 1 @@ROWCOUNT FROM dbo.tb_CommonDataDict --方法2if exists(SELECT TOP 1 * FROM dbo.tb_CommonDataDict )--方法3if (select Count(*) from a)>0
create or replace procedure data_move(param in number) is cursor enterprise is select SENTERPRISEID, SSPECIALNUMBER, NSPECIALNUMBERTYPE FROM e_uc_specialcode; enter char(10); spnumber VARCHAR2(32); sptype number; id number; begin open enterprise; id:
语法: update table1 set table1.列=table2.列 from table2 where table2.列=table1.列update dbo.PATIENT setPATIENT_ADDUSERID=OLD.PATIENT_ADDUSERID,PATIENT_UPDATEUSERID=OLD.PATIENT_UPDATEUSERID,PATIENT_UPDATEUSERNAME=OLD.PATIENT_UPDATEUSERNAME,PATIENT_ADDUS
