一个简单的小算法来获取两个数的最大公约数, public class Test { public static void main(String[] args) { long result = gcd(15, 3); System.out.println(result); } public static long gcd(long m, long n) { while (n != 0) { long rem = m % n; m = n; n = rem; } return m; } }
公式法:两个数相乘等于最小公倍数乘以最大公约数 #define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <stdlib.h> int gcd2(int a, int b) { int mod = a%b; ) { a = b; b = mod; mod = a%b; } return b; } int main() { int a, b; int cd; scanf("%d", &a); s
Given two integers dividend and divisor, divide two integers without using multiplication, division and mod operator. Return the quotient after dividing dividend by divisor. The integer division should truncate toward zero. Example 1: Input: dividend
js中,如何返回两个数的商的整数和余数部分? 如: num1:100 ,num2:12 var num = parseFloat(100/12); //值: 8.333333333333334 那么如何返回整数/余数,返回结果 8/4 js的方法 //计算件数(产品数量/包装数量) var JsPieceNum = function(num1,num2){ var pieNum = parseFloat(num1/num2); var result=""; //判断是否为浮点数(100