两种方式: 第一种是利用笛卡尔积,两对比排序 -- 学校类型数据 SELECT t.examid,'-' AS unitcode,t.schooltype,'-' AS classname,t.bkrs,t.skrs,t.avgs, ))-t.avgrank AS avgrank, t.anum,t.aratio, ))-t.arrank AS arrank, t.bnum,t.bratio, ))-t.brrank AS brrank, ' AS ordernum FROM ( SELECT
题目链接 题目大意:对链表进行插入排序. 解法:直接插入排序.代码如下(耗时40ms): public ListNode insertionSortList(ListNode head) { ListNode first = new ListNode(0); ListNode pre = first, cur = head, post = null; while(cur != null) { //保存cur.next,因为要遍历当前结点,下一次就要遍历当前结点的下一个结点,所以在这次遍历完之后需
t = { [] = , [] = , [] = } for k, v in pairs(t) do--注意这个输出顺序是没有规律的!!! print(k, v) end local keys = {} for k, _ in pairs(t) do table.insert(keys, k) end function cmp(v1, v2) return v1 > v2 end print("---------------------") table.sort(keys, fu
I Count Two Three 二分查找用lower_bound 这道题用cin,cout会超时... AC代码: /* */ # include <iostream> # include <cstring> # include <string> # include <cstdio> # include <cmath> # include <algorithm> using namespace std; const int TWO
SQL> create user scan identified by scan default tablespace users; User created. SQL> grant dba to scan; Grant succeeded. create table t1 (id char(10) primary key,a1 char(10),a2 char(10)); begin for i in 1 .. 25 loop insert into t1 values(i,i,'a'||i