1.题目描述 大家都知道斐波那契数列,现在要求输入一个整数n,请你输出斐波那契数列的第n项(从0开始,第0项为0). 递归实现: class Solution(): def Fibnacci(self,n): if n <= 0: return 0 if n == 1: return 1 return self.Fibnacci(n-1) + self.Fibnacci(n-2) 非递归实现: def Fibnacci(n): result = [0,1] if n <= 1: return
一.三元运算 三元运算又称三目运算,是对简单的条件语句的简写,如: 简单条件处理: if 条件成立: val = 1 else: val = 2 改成三元运算 val = 1 if 条件成立 else 2 二.智能检测文件编码 用第三方模块chardet 首先要安装chardet模块 ,用pip命令进行安装 chardet的用法 import chardet f = open("staff_table.txt","rb") data =f.read() f.clos
递归.递推计算斐波那契数列第n项的值: #include <stdio.h> long long fact(int n); //[递推]计算波那契数列第n个数 long long fact2(int n);//[递归] int main(int argc, char *argv[]) { ; ) { printf("%d %I64d %I64d\n",i,fact(i),fact2(i)); i++; } ; } long long fact(int n) //[递推]计算
本题来自 Project Euler 第2题:https://projecteuler.net/problem=2 # Each new term in the Fibonacci sequence is generated # by adding the previous two terms. # By starting with 1 and 2, the first 10 terms will be: # 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... # By
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace 斐波那契数列求和 { class Program { static void Main(string[] args) { Console.WriteLine()); Console.WriteLine()); Console.WriteLine()
# coding=utf-8 # Fibonacci.py Fib = {} def Fibonacci(n): global Fib if Fib.has_key(n): return Fib[n] if n == 0: return 1 if n == 1: return 1 Fib[n] = Fibonacci(n-1) + Fibonacci(n-2) return Fib[n] if __name__ == '__main__': for i in range(50): print F
先占坑 后面再写详细的 import numpy as np def pow(n): a = np.array([[1,0],[0,1]]) b = np.array([[1,1],[1,0]]) n -= 1 while(n > 0): if (n % 2 == 1): a = np.dot(b, a) b = np.dot(b, b) n >>= 1 return a[0][0] n = int(input()) print(factorial(n))
