def is_Sublist(l, s): sub_set = False if s == []: sub_set = True elif s == l: sub_set = True elif len(s) > len(l): sub_set = False else: for i in range(len(l)): ]: n = while (n < len(s)) and (l[i+n] == s[n]): n += if n == len(s): sub_set = True retu
1.需求 num = [1,2,2,2,3,4,2,2,2,2,2,2,22,2]把列表中的有2的元素全部删除 2.编程代码 nums = [1,2,2,2,3,4,2,2,2,2,2,2,22,2]print("打印删除前的元素:")print(nums)temp = []for i in nums: if i !=2 and "2" is not str(i): temp.append(i)print("打印删除后的元素:&quo
data={"} ,{"}]} print("before:\n\n",data,"\n\n") temp=- k= for i in data['data']: if(i["name"]=="a3"): temp=k break k=k+ ): del data['data'][temp] print("after:\n\n",data)