public static void main(String[] args) { Scanner scan = new Scanner(System.in); Point point1 = new Point(); Point point2 = new Point(); double x, y; point1.setLocation(5.0, 5.0); point2.setLocation(1.0, 1.0); System.out.println("请分别输入点x,y的坐标:");
A Round Peg in a Ground Hole Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 4438 Accepted: 1362 Description The DIY Furniture company specializes in assemble-it-yourself furniture kits. Typically, the pieces of wood are attached to on
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4311 解题报告:在一个平面上有 n 个点,求一个点到其它的 n 个点的距离之和最小是多少. 首先不得不说一下做这道题囧的事,杭电用的是__int64,我前面定义的时候用的是__int64,然后后面输出结果的时候格式控制符竟然用了%lld,还小卡了一会,唉,大意了啊. 然后感觉这题好巧妙,做法是将 x 与 y的距离分开求,我也是看了学长博客之后才懂的http://www.cnblogs.com/Lyu
UI3D转2D平面显示UI3DTo2D血条显示: using UnityEngine; using System.Collections; public class UI3DTo2D : MonoBehaviour { private GameObject _TargetEnemyObj; //目标物体 private Camera worldcamera; //世界相机 private Camera guiCamera
http://acm.hdu.edu.cn/showproblem.php? pid=5372 Segment Game Time Limit: 3000/1500 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 1284 Accepted Submission(s): 375 Problem Description Lillian is a clever girl so