package a; public class ShuZi { int m; public int getM() { return m; } public void setM(int m) { this.m = m; } public void shu() { System.out.println("输入的数字是:"+m); if(m>99999) { System.out.println("The number is too large"); } else
原题链接:http://ac.jobdu.com/problem.php?pid=1525 字符串简单题,注意开有结尾有空格的情况否则pe or wa #include<algorithm> #include<iostream> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> using std::
How to read a file in reverse order? import os def readlines_reverse(filename): with open(filename) as qfile: qfile.seek(0, os.SEEK_END) position = qfile.tell() line = '' while position >= 0: qfile.seek(position) next_char = qfile.read(1) if next_cha
<span style="color:#FF0000;">第一步:把输入的数字转为字符串n.ToString() 第二步:求出字符串的长度即为正整数的位数 第三步:从后向前逆序输出</span> 附代码: using System; using System.Collections.Generic; using System.Linq; using System.Text; //给一个正整数, //要求:一.求它是几位数,二.逆序打印出各位数字. namespa
python列表和字符串的三种逆序遍历方式 列表的逆序遍历 a = [1,3,6,8,9] print("通过下标逆序遍历1:") for i in a[::-1]: print(i, end=" ") print("\n通过下标逆序遍历2:") for i in range(len(a)-1,-1,-1): print(a[i], end=" ") print("\n通过reversed逆序遍历:") f