python中判断某一个元素是否在一个列表中,可以使用关键字in 和 not in. 示例如下: 如果需要输出相应的信息,可以搭配使用if语句,这里不赘述. ------------------------------------------------------------------------------------------分割线------------------------------------------------------------------------------
#小游戏,摇筛子押大小的小游戏玩家初始有1000块钱,可以压大压小作为赌注 import random #定义摇筛子的函数: def roll_dice(number = 3,points = None): print ('<<<<< Roll The Dice >>>>>') if points is None: points = [] while number > 0: point = random.randrange(1,7) poi
下面提供一种利用os.walk()快捷的计算指定文件夹大小的方法 话不多说,直接上代码 简略版: import os def get_file_size(file_path, size=0): for root, dirs, files in os.walk(file_path): for f in files: size += os.path.getsize(os.path.join(root, f)) # 加上下面一行打印所有文件 # print(f) return size print(g
#!/usr/bin/env python import osimport sys def read_file(fpath): Block_Size = 1024 with open(fpath,"r") as f: while True: block = f.read(Block_Size) if block: yield block else: return for i in read_file(sys.argv[1]): print(i)
问题描述: select * from users where user_name ='user_01' 跟 select * from users where user_name ='uSer_01',select * from users where user_name ='uSEr_01' 等等的查询结果一样,我们发现只是查询的字母大小写不一样,但是查询结果却相同. 这是mysql 默认设置,只要加入 binary 就可以解决这个问题 select * from users where b
__author__ = 'bruce' import os from os.path import join,getsize def getdirsize(dir): size=0l for (root,dirs,files) in os.walk(dir): for name in files: try: #print getsize(join(root,name)) size += getsize(join(root,name)) except: continue #直接用下面这句代码,在