TypeError: cannot concatenate 'str' and 'int' objects 1. print 'Is your secret number " + str(p) + "?"2. print 'Is your secret number %d?"%p (for multiple integers, you can '%d %d %d'%(num1, num2, num3)3. print 'Is your secret number {
java中int,float,long,double取值范围是多少? 写道 public class TestOutOfBound { public static void main(String[] args) { System.out.println(Integer.MAX_VALUE-(-Integer.MAX_VALUE)); //内存溢出System.out.println(Integer.MAX_VALUE); //2的31次方-1,10个数位,正的20亿左右,用在钱上面不一定够Sy
1.问题描述 age=input('please enter your age') if age >=18: print('your age is',age) print('adult') elif age>=6: print('teenager') else: print('kid') 今天在运行该代码的时候,python解释器报错,错误信息如下: F:\python>python3 elif.pyplease enter your age5Traceback (most recent
Qt中 int ,float ,double转换为QString 有两种方法 1.使用 QString::number(); 如: long a = 63; QString s = QString::number(a, 10); // s == "63" QString t = QString::number(a, 16).toUpper(); // t == "3F" (解释,变量a为int型或者float,double.10和16为进制) toUpper是大写
先看一段代码实验: #include<limits> #include<iostream> using namespace std; int main() { unsigned int i = numeric_limits<unsigned int >::max(); float f = i; unsigned int j = (unsigned int )f; bool flag 1 = i==j; cout<<"i = "<&l