利用上一篇得到的城市经纬度算城市距离 import requests from math import radians, cos, sin, asin, sqrt def geocode(address): url= 'http://api.map.baidu.com/geocoder?output=json&key=f247cdb592eb43ebac6ccd27f796e2d2&address='+str(address) response = requests.get(url) an
文本进度条实例 #!/usr/bin/env python3 import time #for i in range(101): # print ("\r{:3.0f}%".format(i),end="") # time.sleep(0.1) scale = 50 print("执行开始".center(scale//2,"-")) start = time.perf_counter() for i in range(sca
chr 数字转换字母 r = chr(65)print(r) ord字母转换数字n = ord("A")print(n) random 函数 import random li = []for i in range(6): temp = random.randrange(65, 91) c = chr(temp) li.append(c)result = " ".join(li)print(result) 生成随机验证码import random li = []for
有这样一个有关最大公约数的函数:函数 f(x, y): { c=0 当 y>0: { c +=1 t = x % y x = y y = t } 返回 c * x * x} 给出三个正整数n,m,p,你需要计算: ∑i=1n∑j=1m⌊i∗jf(i,j) 对p取模的结果. #include <stdio.h> #include <iostream> #include <stack> #include <algorithm> #include <c