Given a list, rotate the list to the right by k places, where k is non-negative. For example:Given 1->2->3->4->5->NULL and k = 2,return 4->5->1->2->3->NULL. 这道旋转链表的题和之前那道Rotate Array 旋转数组 很类似,但是比那道要难一些,因为链表的值不能通过下表来访问,只能一个一个的
Given a linked list, rotate the list to the right by k places, where k is non-negative. Example 1: Input: 1->2->3->4->5->NULL, k = 2 Output: 4->5->1->2->3->NULL Explanation: rotate 1 steps to the right: 5->1->2->3-&g
Rotate an array of n elements to the right by k steps. For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4]. Note:Try to come up as many solutions as you can, there are at least 3 different ways to solve this pro
-moz-transform: rotate(5deg);-webkit-transform: rotate(5deg); 把图片旋转了5度.本以为轻而易举,可遇到了问题.在Fireofx中显示正常,但在webkit内核下的浏览器中,如Chrome和Safari,图片边缘会有很明显锯齿.也可以说是webkit抗锯齿的一个BUG.另外需要补充的一点,如果图片上级元素含有overflow:hidden;属性,则会让锯齿感更明显. 通过查找相关的资料,终于找到了解决办法.便是使用CSS3 3D tra
Given an array, rotate the array to the right by k steps, where k is non-negative. 给定一个数组,并且给定一个非负数的值k, 把数组往右旋转k步,要求不返回新的数组,直接改变原数组 例子1: 给定数组: [1,2,3,4,5,6,7] 给定 k = 3 输出数组: [5,6,7,1,2,3,4] 解析: 往右旋转1步: [7,1,2,3,4,5,6] 往右旋转2步: [6,7,1,2,3,4,5] 往右旋转3步: