2.1 Write code to remove duplicates from an unsorted linked list.FOLLOW UPHow would you solve this problem if a temporary buffer is not allowed? 这道题让我们移除无序链表中的重复项,在LeetCode中有两道类似的题是Remove Duplicates from Sorted List 移除有序链表中的重复项 和 Remove Duplicates fr
[试题描述]定义一个函数,输入一个链表,删除无序链表中重复的节点 [参考代码] 方法一: Without a buffer, we can iterate with two pointers: "current" does a normal iteration, while "runner" iterates through all prior nodes to check for dups Runner will only see one dup per node
无序集合: 首先介绍增加,删除和获得所有元素的方法.我将会用第二部分来讨论集合的特殊操作: In [136]: x.sadd("challenge", 1,2,3,4,5,6,7,5,4,4,3,4,2) 7 In [138]: x.smembers("challenge") set([']) In [139]: x.srem("challenge", 1, 3) 2 In [140]: x.smembers("challenge&qu
https://cloud.tencent.com/developer/article/1347437 python中的Redis键空间通知(过期回调) set notify-keyspace-events KEA [KEA参照以下字符进行设置]此有缺点:最大的缺点是Pub / Sub实现要求发布者和订阅者一直处于启动状态.订阅服务器在停止或连接丢失时会丢失数据. [意思:就是如果服务端在意外情况下出现重启或断开,需要重新设置(windows)] 字符 发送通知 K 键空间通知,所有通知以 k
keys pattern 查询相应的key 在redis里,允许模糊查询key 有3个通配符 *, ? ,[] *: 通配任意多个字符 ?: 通配单个字符 []: 通配括号内的某1个字符 redis 127.0.0.1:6379> flushdb OK redis 127.0.0.1:6379> keys *//查所有 (empty list or set) redis 127.0.0.1:6379> mset one 1 two 2 three 3 four 4 OK redis 12