JS获取url请求参数,代码如下: // 获取url请求参数 function getQueryParams() { var query = location.search.substring(1) var arr = query.split('&') var params = {} for (var i = 0; i < arr.length; i++) { var pair = arr[i].split('=') params[pair[0]] = pair[1] } console.l
本文为博主原创,未经允许不得转载: 1.对常用调用的方法进行封装: import org.springframework.http.HttpHeaders; import com.alibaba.fastjson.JSONObject; public interface SpringRestService { public <T> T postWithJson(String url, JSONObject param, Class<T> responseType); public
最近使用RestTemplate发送post请求,遇到了很多问题,如转换httpMessage失败,中文乱码等,调了好久才找到下面较为简便的方法: RestTemplate restTemplate = new RestTemplate(); HttpHeaders headers = new HttpHeaders(); MediaType type = MediaType.parseMediaType("application/json; charset=UTF-8"); head
<?phpdefine('DS','/');define('A_PATH',str_replace('\\','/',dirname(__FILE__)).DS); //01获取到主程序目录class a {public $app,$controller,$action,$class,$client;public function __construct($client){$this->client = $client;}public function execute(){ $this->