stuff(select ',' + fieldname from tablename for xml path('')),1,1,'') 这一整句的作用是将多行fieldname字段的内容串联起来,用逗号分隔.例如表fieldname-----------AAABBBCCC串联之后就是字符串: AAA,BBB,CCCfor xml path是SQL Server 2005以后版本支持的一种生成XML的方式.具体如何使用,请参考联机丛书.stuff函数的作用是去掉字符串最前面的逗号分隔符. --
with temp as( select 'China' nation ,'Guangzhou' city from dual union all select 'China' nation ,'Shanghai' city from dual union all select 'China' nation ,'Beijing' city from dual union all select 'USA' nation ,'New York' city from dual union all se
思路: 先将取出的值随机排序,然后在随机排序的每次取第一条的结果 举例如下: select * from(select t.code fromTBIZOPS_PROVINCE t ORDER BY DBMS_RANDOM.RANDOM())where rownum < 2;select * from (select t.code from TBIZOPS_CITY t wheret.province_id = '13' ORDER BY DBMS_RANDOM.RANDOM()) where
11g里面用listagg: select listagg(name,',') within (order by id) from table 10g里面用wm_concat:select wm_concat(name) from table wm_concat是undocument的listagg是11g document的
USE [FM_Dev] GO /****** 对象: UserDefinedFunction [dbo].[GetClassNameByStudentCode] 脚本日期: 05/23/2014 17:20:43 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO -- ============================================= -- Author: -- Create date: 2014年5月7日
未合并情况 SELECT a.id, b.name AS "role" FROM sys_user a INNER JOIN sys_user_role c ON a.id=c.user_id INNER JOIN sys_role b ON b.id =c.role_idWHERE a.del_flag=0 AND b.del_flag=0 结果 id role 1 系统管理员1 测试角色2 系统管理员2 测试角色9 系统管理员9 测试角色d11828f3dbf148829287a
SELECT po.id,(SELECT GROUP_CONCAT(mr.member_type) as memberTypeList FROM prod_offer_member_rel mr WHERE mr.prod_offer_id = po.id) as memberTypeListfrom prod_offer po
原SQL AND acc.id = accRole.acc_id) AND accRole.role_id = T_PM_ROLE.id ORDER BY acc.id 结果,有一个人有两个角色,如果想要将两个角色合并该如何呢? 答案:使用 group_concat函数 注:group_concat只有与group by语句同时使用才能产生效果 AND acc.id = accRole.acc_id) AND accRole.role_id = T_PM_ROLE.id GROUP BY acc
var rowData = ajaxgrid.getSelectedRow(); var quality = rowData["quality"]; var rowIndex = rowData["rowIndex"]; var record = ajaxgrid.getRecord(rowIndex); if(quality==111){ record.set("source", "-3"); }
今天无意中碰到一个很简单的计算逻辑,但是用hive想了一大会才实现. 示例表数据: 需求逻辑: 给每条记录追加一个字段,用于统计按照p1和p2字段分组后,每个组中的num的数目(去重后的count). 示例结果: Mysql 超级简单的一句: select id, num, p1, p2, count(distinct num) over (PARTITION by p1,p2) as f from test_z; Hive里 会报distinct有问题,去掉的话,明显与要求逻辑不符合啊. 想了
oracle查询:取出每组中的第一条记录按type字段分组,code排序,取出每组中的第一条记录 方法一: select type,min(code) from group_info group by type; 注意:select 后面的列要在group by 子句中,或是用聚合函数包含,否则会有语法错误. 方法二: SELECT * FROM(SELECT z.type , z.code ,ROW_NUMBER()OVER(PARTITION BY z.type ORDER BY z.cod
例如student表: studentID studentName studentScore 01 Alice 90 02 Bill 95 03 Cindy 100 一.拼接多个字段的值 select studentID+‘-’+studentName+'-'+studentScore AS studentInfo from student 结果: 二.一个字段多条记录的拼接 select stuff((select '|'+studentName from student for xm
如student表: studentID studentName studentScore 01 Alice 90 02 Bill 95 03 Cindy 100 一.拼接多个字段的值 select studentID+‘-’+studentName+'-'+studentScore AS studentInfo from student 结果: 二.一个字段多条记录的拼接 select stuff((select '|'+studentName from student for xml p