/*取今年第一天,取今年最后一天*/ SELECT trunc(sysdate, 'yyyy') AS 今年第一天 , add_months(trunc(sysdate, ) AS 今年最后一天 FROM dual; 效果如下: 不忘初心,如果您认为这篇文章有价值,认同作者的付出,可以微信二维码打赏任意金额给作者(微信号:382477247)哦,谢谢.
/*取本周第一天(星期一),取本周最后一天(星期天)*/ SELECT trunc( SYSDATE, AS 星期一 , trunc( SYSDATE, AS 星期天 FROM dual; 效果如下: 不忘初心,如果您认为这篇文章有价值,认同作者的付出,可以微信二维码打赏任意金额给作者(微信号:382477247)哦,谢谢.
好吧 QQ群里被问到这种问题,还是这里写一下吧. DECLARE @date DATETIME = getdate(); SELECT EOMONTH (@date) AS 'Last Day Of This Month', EOMONTH (@date, 1) AS 'Last Day Of Next Month', EOMONTH (@date, -1) AS 'Last Day Of Previous Month', EOMONTH (@date, -2) AS 'LAST Last Da
--国内从周一到周日 国外是周日到周六 select to_char(sysdate-1,'D') from dual;--取国内的星期几 去掉减一取国外的星期 --取本周时间内的数据 ,)+) and DTIME<=trunc(next_day(sysdate-,)+)+ ; ,)) and DTIME<=trunc(next_day(sysdate-,)+):--国外的 select * from table where DTIME >=TRUNC(SYSDATE, 'MM') an
var nowdays = new Date(); var year = nowdays.getFullYear(); var month = nowdays.getMonth(); if(month==0){ month = 12; year = year-1; } if(month<10){ month = '0'+month; } var myDate = new Date(year,month,0); var startDate = year+'-'+month+'-01 00:00:0