list中有n个值,赋值给k个变量:a1, a2, ……,ak n = k时:a1, a2, ……,ak = list n > k时:使用1式报错:ValueError: too many values to unpack n < k时:使用1式报错:ValueError: need more than "n" values to unpack 只有n >= k时才可赋值: 从下标i开始的k个元素赋给a1, a2, ..., ak: a1, a2, ..., ak =
The problem here is that you've defined an anonymous method which returns a string but are trying to assign it directly to a string. It's an expression which when invoked produces a string it's not directly a string. It needs to be assigned to a comp
在写存储过程或函数时,经常需要用到中间变量,需要将一些值做临时存储. 可以通过动态变量方式来赋值.如下: FUNCTION YOUR_FUN (VAL1 IN NVARCHAR2) RETURN NCLOB IS PRAGMA AUTONOMOUS_TRANSACTION; ); --中间变量 BEGIN SELECT ID INTO MID_ID FROM TABLE1 ; END; 以上语句在条件A=1满足时,能够成功赋值给变量MID_ID,但如果没有查询到值时,该语句在执行时会报错(因为未
2012-03-25 12:12 a786013819 | 分类:数据库DB | 浏览1393次 $sql = "select field1 from pre_common_member_profile where uid='$username'";得到的结果是这样的:field11234怎么把1234赋值给变量 你是只取这一个值还是要取数组.只取一个的话.$sql = "select field1 from pre_common_member_profile where u
先查询再插入数据库的函数 CREATE OR REPLACE FUNCTION F_REVENUE_SI(l_p_cd in Varchar2, l_c_cd in Varchar2, l_prod_type in Varchar2, l_identity_type in Varchar2, l_industry_type_id in Varchar2, l_p_id in Varchar2, l_c_id in Varchar2, l_region_name in Varchar2, l_in