//学生记录由学号和成绩组成,N名学生的数据已放入主函数中的结构体数组中,fun函数:把分数最低的学生数据放入数组b所指的数组中,分数最低的学生可能不止一个.人数返回. #include <stdio.h> #define N 16 typedef struct { ]; int s; } STREC; int fun( STREC *a, STREC *b ) { STREC *c; c = a; int min = c->s; ; ; i < N; i++) { c++; if
转载:http://my.oschina.net/jasonultimate/blog/166968 1) Since Strings are immutable in Java if you store password as plain text it will be available in memory until Garbage collector clears it and since String are used in String pool for reusability th
第一种方法: HttpWebRequest httpwebr = (HttpWebRequest)HttpWebRequest.Create(rstr); httpwebr.Method = "GET"; Stream s =httpwebr.GetResponse().GetResponseStream(); byte[] buffer = new byte[1024]; int actual = 0; //先保存到内存流中MemoryStream MemoryStream ms =
不吐槽华为的服务器了,直接上正文 输入:字符串(英文字母),长度不超过128 输出:出现频率最高的字母 思路写在注释文档 /* Input a string * Output the most frequent character * * The way of thinking: * using ASCII, count the number of each character * then find out the max number(max_num) * and its according
1.用户输入--input和getpass函数 2.字符串的格式化 ############################################# 一.用户输入--input()函数 #!/usr/bin/env python #-*- coding:utf-8 -*- #name = raw_input("what is your name?") #only on python2.x name = input("what is your name:")
import itertools str = input('请输入一个字符串:') lst = [] for i in range(1, len(str)+1): lst1 = [''.join(x) for x in itertools.permutations(str, i)] lst += lst1 print(lst) 主要使用的itertools库