查询以及删除一个数据库表内的重复数据. 1.查询表中的多余的重复记录,重复记录是根据单个字段来判断的. select * from biao where id in (select id from biao group by id having count(id) >1 ) 2.删除表中的多余的重复记录,重复记录是根据(id)来判断,只留rowid 最小值. delete from biao where id in ( select id from biao group by id h
业务:一个表中有很多数据(id为自增主键),在这些数据中有个别数据出现了重复的数据. 目标:需要把这些重复数据删除同时保留第一次插入的那一条数据,还要保持其它的数据不受影响. 解题过程: 第一步:查出所有要保留的下来的数据的id(save_id) SELECT id as save_id FROM yujing.alarm_event_info_snapshot aeis where aeis.event_id in (SELECT ae.id FROM yujing.alarm_event a
1.删除完全重复数据 原始数据: 期望数据: delete result from (select ROW_NUMBER () over(partition by id order by id) r, * from temp_0814 t ) result where result.r!=1 2.删除查询的前N条记录 原始数据: 期望数据: DELETE TOP (3) FROM temp WHERE id=1
最近在写SQL过程中发现需要对一张表结构作调整(此处是SQL Server),其中需要删除多列,由于之前都是一条SQL语句删除一列,于是猜想是否可以一条语句同时删除多列,如果可以,怎么写法? 第一次猜想如下(注意:此处是猜想,非正确的写法): ALTER TABLE TableName DROP COLUMN column1,column2 但是执行后,发现语法错误, 于是改成如下的方式: ALTER TABLE TableName DROP COLUMN column1,COLUMN colu
1.表数据结构如下 select * from test t , 'jerry'); , 'jerry'); , 'jerry'); , 'tom'); , 'tom'); , 'jake'); , 'jake'); , 'jake'); 2.删除sql如下 a.name去重,取最小的字段 b.使用exists删除重复的数据 delete test a where not exists ( select * from (select min(id) id, name from test grou
delete from test where id in (select id from (select max(id) as id,count(text) as count from test group by text having count >1 order by count desc) as tab ) 测试代码 INSERT IGNORE INTO test_1(text,text2) values ('1111','22222'); INSERT IGNORE INTO t
SELECT TOP (500) ID, Personname, Personcode, Telphone, Fraction into temp3 FROM Records AS a WHERE (LEN(Personcode) = 18 OR LEN(Personcode) = 15) AND (NOT EXISTS (SELECT 1 AS Expr1 FROM Records WHERE (Personname = a.Personname) AND (Fraction > a.Frac
在网上看过一些解决方法 我在此给出的方法适用于无唯一ID的情形 表:TB_MACVideoAndPicture 字段只有2个:mac,content mac作为ID,正常情况下mac数据是唯一的,由于操作失误导致数据插入多次,导致出现多个mac,content重复数据,现在只保留一条,删除多余的 大体思想是给重复数据一个自增ID,过滤出每组里面最小ID,删除原数据中所有重复数据再将最小ID插入 --查询出所有重复数据,并给定递增id , ) AS id , mac , content INTO
写了好几年的sql,having语句基本上很少写,这就有一点尴尬了,现在总结一下having的作用,每日整理一下学习文档. having 通常伴随group by使用,过滤group by的数据集. 比如找到重复的数据: select card_id,count(*) from 502_account group by card_id HAVING count(1)>1 找到找到重复的card_id 如果要找到金额大于500 select card_id from 502_drug_sale g
最近面试中都遇到了这样一个数据库题: 删除表中的重复数据,有且只保留一条重复数据. 思路: 1)这个题需要用到rowid,首先找到重复数据的rowid,并找出rowid最大或最小值,作为删除的条件: select min(rowid) from aa group by Name having count(Name) > 1 2)根据name找出数量大于1的name select name from aa group by name having count(name) > 1 3)根据上两个条
sql去重 先根据需要去重的字段进行分组,取到主键值最小的记录(id 是主键,删除重复的 record_id 的记录) select min(id) from tb_traffic_wf_record t group by t.record_id 然后删除不在上面的记录里的数据,就行了 delete from tb_traffic_wf_record where id not in (select min(id) from tb_traffic_wf_record as t group by t
表结构: LOAD DATA INFILE '/usr/local/phone_imsi_12' replace INTO TABLE tbl_imsi2number_new FIELDS TERMINATED BY '\t' ENCLOSED BY '' (number,imsi); 先用SQL语句来进行去重操作: delete from tbl_imsi2number_new where imsi in (select imsi from (select imsi from tbl_imsi