.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select*from people where peopleIdin (select peopleIdfrom peoplegroupby peopleIdhaving ) .删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有rowid最小的记录 deletefrom people where peopleIdin (select peopleIdfrom peoplegroupby pe
( SELECT sum( a.cost_sum ) AS sum_cost, sum( a.phone_sum ) AS sum_phone, sum( a.arrive_sum ) AS sum_arrive, FORMAT( ) AS arrive_cb, a.time AS time FROM ( SELECT FROM_UNIXTIME( time, "%Y-%m-%d" ) AS time, sum( cost ) AS cost_sum, sum( arrive_true
select b.NativeName from sanleiDB.dbo.Dictionary_Native b where not EXISTS (select a.NativeName from Dictionary_Native a where a.NativeName = b.NativeName)union select a.NativeName from Dictionary_Native a where not exists (select b.NativeName from s
CREATE TABLE [TestTable] ( ) NOT NULL , ) NOT NULL , ) ))) GO ALTER TABLE [TestTable] ADD PRIMARY KEY ([uid], [key]) GO ) GO ) GO ) GO ) GO ) GO ) GO WITH cte AS ( SELECT *, ROW_NUMBER() OVER (PARTITION BY uid ORDER BY [key] DESC) AS rn FROM vtable )
方法一: select t1.num1,t2.num2,t3.num3 from (select count(*) num1 from table1) t1, (select count(*) num2 from table2) t2, (select count(*) num3 from table3) t3 方法二: select sum(t.num1),sum(t.num2),sum(t.num3) from ( as num3 from table1 union as num3 from
刚有个项目,需要查询水位数据表中的水位信息,及查询降雨量表中统计时段降雨量的数据,以计算出日降雨量,而且时段是前一天8时到后一天8时总共24个小时. 两个子查询: 1.根据当前时间判断统计前天8时到今天8时还是大前天8时到前天8时的时段雨量: select STCD,SUM(DRP) as drp2 from Jialiang.dbo.ST_PPTN_R where STCD'and TM>case ), , )), , )+' 8:00' end and TM<case ), )), , )
1.in和exists in是把外表和内表作hash(字典集合)连接,而exists是对外表作循环,每次循环再对内表进行查询.一直以来认为exists比in效率高的说法是不准确的,如果查询的两个表大小相当,那么用in和exists差别不大:如果两个表中一个较小一个较大,则子查询表大的用exists,子查询表小的用in. 例如:表A(小表),表B(大表) 方式一:索引使用 1)select * from A where id in(select id from B) -->效率低,用到了A表上id