关键字PARTITION BY 自己看代码喽~ SELECT * FROM ( SELECT ROW_NUMBER() OVER (PARTITION BY ClassType ORDER BY Score DESC) rowid, ClassType, Name, Score FROM dbo.CAMAIN ) TT ;
查询数据库里所有表名和字段名的语句SQL 查询所有表名:SELECT NAME FROM SYSOBJECTS WHERE TYPE='U'SELECT * FROM INFORMATION_SCHEMA.TABLES查询表的所有字段名:SELECT NAME FROM SYSCOLUMNS WHERE ID=OBJECT_ID(' 表名' )SELECT * FROM INFORMATION_SCHEMA.TABLESSELECT * FROM INFORMATION_SCHEMA.VIEWS
创建表:Create table If Not Exists Employee (Id int, Name varchar(255), Salary int, DepartmentId int);Create table If Not Exists Department (Id int, Name varchar(255));Truncate table Employee;insert into Employee (Id, Name, Salary,DepartmentId) values ('
ms sql server 1.查询所有表select [id], [name] from [sysobjects] where [type] = 'u' order by [name]2.查询所有数据库3.select [name] from [sysdatabases] order by [name]查询表中字段 select [name] from [syscolumns] where [name] = 'tableXXX'order by [colid] oracle 1.查找表的所有索
--1.查看所有表名:select name from sysobjects where type='U'--2.查找包含用户的表名,可通过以下SQL语句实现, Select * From sysobjects Where name like '%20160222%' and crdate>'2016-02-22 16:19:31'
select sname from student where not exists (select * from course where not exists (select * from sc where sno =student.sno and cno=course.cno); 最内部的 select * from sc where sno=student.sno and cno = course.cno是查询出所有已经选择过课程的学生及相应课程,select * from cour
--创建视图 create view StuClassView as SELECT s.ID ,s.StuName ,s.StuAge ,s.StuAddress ,s.StuTel ,s.ClassId ,s.StuId,s.StuSex ,e.ClassName,e.ClassInfo,e.ClassFlag FROM Classes as e left join Students as s on s.ClassId=e.ClassId end) as '男', end) as '女' fr
问题 在工作中常会遇到将数据分组排序的问题,如在考试成绩中,找出每个班级的前五名等. 在orcale等数据库中可以使用partition语句来解决,但在mysql中就比较麻烦了.这次翻译的文章就是专门解决这个问题的 原文地址: How to select the first/least/max row per group in SQL 翻译 在使用SQL的过程中,我们经常遇到这样一类问题:如何找出每个程序最近的日志条目?如何找出每个用户的最高分?在每个分类中最受欢迎的商品是什么?通常这类"找出每
问题 在工作中常会遇到将数据分组排序的问题,如在考试成绩中,找出每个班级的前五名等. 在orcale等数据库中可以使用partition 语句来解决,但在MySQL中就比较麻烦了.这次翻译的文章就是专门解决这个问题的 原文地址: How to select the first/least/max row per group in SQL 翻译 在使用SQL的过程中,我们经常遇到这样一类问题:如何找出每个程序最近的日志条目?如何找出每个用户的最高分?在每个分类中最受欢迎的商品是什么?通常这类“找
原文地址: https://blog.csdn.net/tim_phper/article/details/54963828 select select * from student; all 查询所有 select all sex from student; distinct 过滤重复 select distinct sex from student; count 统计 select count(*) from student; select count(sex) from student;