SELECT CONVERT(VARCHAR(10), dtCreateTime, 120) AS dtStatisticsCreateDate, COUNT(1) AS nStatisticsCount FROM Web_Statistics WHERE datepart(hh,dtCreateTime)>=10 AND datepart(hh,dtCreateTime)<11
select COUNT(*) from (表名) where (时间字段)between '2012-05-01 00:00:00' and '2012-05-31 23:59:59' 获取ASP.NET时间控件选中的时间 string qishi= Calendar1.SelectedDate.ToString();
1. 查询:以“周”为单位 --查询以下时间段内分别有几周 --时间段:“2017-09-01”到“2017-10-1” select number as wknum from master..spt_values where type='p' AND number>=datepart(wk,'2017-9-1') and number<= datepart(wk,'2017-10-1') 结果如下图 2. 查询:以“月”为单位 --查询以下时间段内分别有几月 --时间段:“2017-09
1.关于SQL查询效率,100w数据,查询只要1秒,与您分享:机器情况p4: 2.4内存: 1 Gos: windows 2003数据库: ms sql server 2000目的: 查询性能测试,比较两种查询的性能 SQL查询效率 step by step -- setp 1.-- 建表create table t_userinfo(userid int identity(1,1) primary key nonclustered,nick varchar(50) not null defau
一.查询数值型数据: SELECT * FROM tb_name WHERE sum > 100; 查询谓词:>,=,<,<>,!=,!>,!<,=>,=< 二.查询字符串 SELECT * FROM tb_stu WHERE sname = '小刘' SELECT * FROM tb_stu WHERE sname like '刘%' SELECT * FROM tb_stu WHERE sname like '%程序员' SELECT * FROM
SQL查询今天.昨天.7天内.30天 今天的所有数据:select * from 表名 where DateDiff(dd,datetime类型字段,getdate())=0 昨天的所有数据:select * from 表名 where DateDiff(dd,datetime类型字段,getdate())=1 7天内的所有数据:select * from 表名 where DateDiff(dd,datetime类型字段,getdate())<=7 30天内的所有数据:select * fro
1.关于SQL查询效率,100w数据,查询只要1秒,与您分享:机器情况p4: 2.4内存: 1 Gos: windows 2003数据库: ms sql server 2000目的: 查询性能测试,比较两种查询的性能 SQL查询效率 step by step -- setp 1.-- 建表create table t_userinfo(userid int identity(1,1) primary key nonclustered,nick varchar(50) not null defau
如何用一个SQL查询出一个班级各个学科第N名是谁? 首先贴出建表语句,方便大家本地测试: -- 建表语句 CREATE TABLE score ( id INT NOT NULL auto_increment, `name` VARCHAR (20) NOT NULL DEFAULT '' COMMENT '姓名', sub VARCHAR (20) NOT NULL DEFAULT '' COMMENT '学科', score INT NOT NULL DEFAULT 0 COMMENT '分
--SQL查询每个表的字段数量select b.[name], count(*) As AllCount,ISNULL(ISNULL(sum(case when isnullable=0 then 1 end),null),null) as NotNullCountfrom syscolumns aINNER JOIN( select [id], [name] from [sysobjects] where [type] = 'u' ) AS b ON a.id = b.[id] GROUP b
1秒查原本递归的查询. 适用于:上下级.多层查询 -- Get childs by parent id WITH Tree AS ( SELECT Id,ParentId FROM dbo.Node P WHERE P.Id = -- parent id UNION ALL SELECT C.Id,C.ParentId FROM dbo.Node C INNER JOIN Tree T ON C.ParentId = T.Id ) SELECT * FROM Tree -- Get parent