如何用SQL排除重复结果只取字段最大值的记录?要求得到的结果(即是PID相同的记录只取ID值最大的那一条). select * from [Sheet1$] a from [Sheet1$] where PID=a.PID and ID>a.ID) select a.* from [Sheet1$] a inner join (select PID,max(ID) as max_id from [Sheet1$] group by PID) b on a.PID=b.PID and a.ID=b
oracle sql日期比较:在今天之前: select * from up_date where update < to_date('2007-09-07 00:00:00','yyyy-mm-dd hh24:mi:ss')select * from up_date where update <= to_date('2007-09-07 00:00:00','yyyy-mm-dd hh24:mi:ss') 在今天只后: select * from up_date where update &
//将日期输入框变为年月的函数方法 var month=0; $('#effectiveDate').datebox({ onShowPanel: function () {//显示日趋选择对象后再触发弹出月份层的事件,初始化时没有生成月份层 span.trigger('click'); //触发click事件弹出月份层 if (!tds) setTimeout(function () {//延时触发获取月份对象,因为上面
sql 中 datetime日期类型字段比较 mysql 可以直接用大于号,也可以用 between and SELECT * FROM staff WHERE UPDATE_DATE >= '2019-08-14 11:41:09' AND UPDATE_DATE <= '2019-08-14 11:41:11'; SELECT * FROM staff WHERE UPDATE_DATE BETWEEN '2019-08-14 11:41:09' AND '2019-08-14 11: