如何实现没有的时间段中使用0来填充?? if object_id('[A]') is not null drop table [A] go create table [A]([日期] datetime,[金额] int) insert [A] select * from [A] union all union all union all declare @stdate smalldatetime, @eddate smalldatetime select @stdate=min([日期]), @
delete from 表名 where id not in (select d.id from (SELECT id FROM 表名 GROUP BY c1,c2,c3,c4)as d) #去重复,把url重复,且区为空的中去掉.select * from TABLE where url in (select u.url from (select * from TABLE where id not in (select d.id from (SELECT id FROM TABLE GROUP
利用SQl对数据库实行数据拆分与组合实现提供以下几种方案: 方法一: WITH CTE AS (SELECT A.Id,A.[Uid],UserName FROM (SELECT A.[id], REPLACE(Split.a.value('.', 'NVARCHAR(max)'),'''','') AS [Uid]FROM (SELECT [id], CAST ('<M>' + REPLACE(Uid, ',', '</M><M>') + '</M>' A