select sname from student where not exists (select * from course where not exists (select * from sc where sno =student.sno and cno=course.cno); 最内部的 select * from sc where sno=student.sno and cno = course.cno是查询出所有已经选择过课程的学生及相应课程,select * from cour
1.复杂SQL查询 1.1.单表查询 (1)选择指定的列 [例]查询全体学生的学号和姓名 select Sno as 学号,Sname as 姓名 from student; select Sno,Sname from student; (2)查询全部列 [例]查询全体学生的详细信息 select * from student; (3)对查询后的指定列进行命名 [例]查询全部学生的“姓名”及其“出生年”两列 select Sname as 姓名,(2014-Sage) as 出生年 from s
真不简单!! 一:使用select语句进行查询 语法: SELECT <列名> FROM <表名> [WHERE <查询条件表达式>] [ORDER BY <排序的列名>[ASC或DESC]] eg1: SELECT SCode,SName,SAddress FROM Students WHERE SSEX = 0 ORDER BY SCode 二:查询所有列和行: eg:
1.相关数据表 Score表 [User]表 SQL语句例如以下: --查询出各科成绩最好的学生信息 --自连接 --SELECT TOP 1 * FROM Score B WHERE B.ScoreName = '数学' ORDER BY B.Score DESC SELECT A.ID,U.Name,A.ScoreName,A.Score FROM Score A,[User]U WHERE UID IN (SELECT TOP 1 UID FR
原文地址: https://blog.csdn.net/tim_phper/article/details/54963828 select select * from student; all 查询所有 select all sex from student; distinct 过滤重复 select distinct sex from student; count 统计 select count(*) from student; select count(sex) from student;
SQL查询记录中增加序列号 根据学生成绩在查询结果中增加排名字段: 1.SELECT ROW_NUMBER() OVER (ORDER BY SCORE ASC) AS RANK,NAME,SCORE FROM GRADE ORDER BY SCORE; 此写法是直接在结果记录添加顺序排序序号 2.SELECT RANK() OVER (ORDER BY SCORE ASC) AS RANK,NAME,SCORE FROM GRADE ORDER BY SCORE; 此写法的根据排序依据列的值进
一.SQL语言查询选修了全部课程的学生的学号和姓名. 两种解决途径: 第一种: 我们可以表示为在SC表中某个学生选修的课程数等于C表中课程总数.相应的SQL语言如下: select S#,SNAME from S where S# in (select S# from SC group by S# --根据Sno分组,统计每个学生选修了几门课程.如果等于C表课程的总数,就是我们要找的S# having count(*) = (select count(*) from C))--统计C表中共有几门
