SQL Server删除重复行是我们最常见的操作之一,下面就为您介绍六种适合不同情况的SQL Server删除重复行的方法,供您参考. 1.如果有ID字段,就是具有唯一性的字段 delect table tableName where id not in ( select max(id) from table group by col1,col2,col3... ) group by 子句后跟的字段就是你用来判断重复的条件,如
参考网址:http://database.51cto.com/art/201103/250046.htm SQL Server数据库多种方式查找重复记录 select * from dbo.T0058_PointObjectGIS ) select c0130_entcode,c0130_entname,COUNT(*) from T0140_EntList group by c0130_entcode,c0130_entname
with list_numbers as ( select Name, AuthorOrTime, Url, Price, EstimatePrice, Size, Category, ROW_NUMBER() over (order by Name, AuthorOrTime, Url, Price, EstimatePrice, Size, Category) as 'rownumber' from Arts ) delete list_numbers where rownumber not
最近发布的脚本,有那种防止重复插入数据(包括存在时更新,不存在是插入的处理,判断的方向可能与下面的示例相反) 使用类似下面的 SQL declare @id int, @value int if not exists( select * from tb where id = @id ) insert tb values( @id, @value ); --else -- update tb set value = @value where id = @id; 或者是使用这种单句的 declar
SELECT st_id FROM ( SELECT *,ROW_NUMBER() OVER( PARTITION BY st_code ORDER BY st_code ) AS num FROM dbo.t_student_info) a 给重复的信息排序,如果信息重复num的值为2,然后查出num=2的数据st_id,然后删除
select company ,count(company) as coun into myls from mylist group by company having count(company)>1 --讲MyList重复的数据放到myls中 declare @id int declare @company varchar(200) declare @td table(id int,address nvarchar(200),linkman nvarchar(100),tel nvarch
1.查询单列重复: select * from test where name in (select name from test group by name having count (name) > 1) 2.查询多列重复: SELECT a.* FROM test a,( SELECT name,code FROM test GROUP BY name,code HAVING COUNT(1)>1 ) AS b WHERE a.name=b.name AND a.code=b.code
DELETE FROM Bus_TerminalMessage_Keywords WHERE Content IN (select Content from Bus_TerminalMessage_Keywords group by Content having count(Content) > 1) AND ID NOT IN (select min(Id) from Bus_TerminalMessage_Keywords group by Content having count(Cont
今天遇到一个历史导入数据重复的问题,于是要删除重复的记录,一开始想用子查询的方式找到要删除记录的id删除,后来发现DELETE语句可以直接用外连接,这样更加简单,效率也更高. delete sys_project from sys_project as aa left join ( select min(id) as id from sys_project group by sysCode ) as bb on aa.id = bb.id where bb.id is null 这里就是通过左外