@ 目录 场景:查询各部门薪水最高的员工. 方法一: 方法二: MySQL group by是如何决定哪一条数据留下的? 分组前的数据: 那么target list和group by column不匹配就一定不能执行吗? MySQL版本:8.0.27 场景:查询各部门薪水最高的员工. CREATE TABLE `employee` ( `id` int NOT NULL AUTO_INCREMENT COMMENT '主键ID', `dept` int NOT NULL COMMENT '部门'
1.列出当前db文件中所有的表的表名 SQL语句:SELECT * FROM sqlite_master WHERE type='table'; 结构如下: 注:网上有人说可以带上db文件的名称,如:SELECT * FROM dbname.sqlite_master WHERE type='table'; 但我试了不行...难道我姿势不对~ 2.判断某表是否存在SQL语句:select count(*) from sqlite_master where type='table' and nam
最近搞Sqlite本地查询,需求为查询某时间段内的数据,在SQL中我们都知道为: select * from tblName where rDate Between '2008-6-10' and '2008-6-12' select * from tblName where rDate Between '2008-6-10' and '2008-6-12' 这样子是没有问题的,但是在Sqlite中我们这样子写是得不到结果的,试了好多次终于发现在规律,我们写成如下: select * from
今天工作时遇见一个数据查询分组问题,就是将分组后同一组数据某一列合并为一行,因为之前很少用到,这次工作中刚好有用到,所以手痒难耐,将它记录下来. 查询sql如下: select t.province_code provinceCode, listagg(t.city_code || '-' || t.city_name, ',') within group(order by t.city_code) city from city t group by t.province_code; 查询效果如
一.PHP+Mysql多条件-多值查询示例代码: index.html代码:<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" " <html><head><meta http-equiv="Content-Type" content="text/html; charset=UTF-8"><title>SQL多
SELECT C.name,value FROM sys.columns C INNER JOIN sys.tables T ON C.object_id = T.object_idINNER JOIN sys.extended_properties P ON p.minor_id=c.column_id AND p.major_id=C.object_id WHERE T.name='SalesSupOrderB'
SELECT ORDINAL_POSITION AS Colorder, Column_Name AS ColumnName, data_type AS TypeName, COLUMN_COMMENT AS DeText, ( CASE WHEN data_type = 'float' OR data_type = 'double' OR data_type = 'decimal' THEN NUMERIC_PRECISION ELSE CHARACTER_MAXIMUM_LENGTH END
搜索距现在六个月前的月份第一天日期: SELECT date('now','start of month','-6 month','0 day'); 搜索距现在六个月前的日期: SELECT date('now','-6 month','0 day'); case when 用法: 栗子: select case when a = "1" then "v" end from table; or select case a when "1" the