SELECT t.card_number ,) AS "省份", SUBSTR(t.card_number,,) "出生年月", SUBSTR(t.card_number,,) "性别" , CASE (SUBSTR(t.card_number,,)%) WHEN THEN '男' WHEN THEN '女' END AS '性别' FROM user t ;
[抄题]: Given two strings s1 and s2, write a function to return true if s2 contains the permutation of s1. In other words, one of the first string's permutations is the substring of the second string. Example 1: Input:s1 = "ab" s2 = "eidbaooo