array = (1..10).to_a # 方法1 length = array.length length.times do |t| print "#{array[t]} " end puts "\n" # 方法2 length = array.length-1 for i in 0..length do print "#{array[i]} " end puts "\n" # 方法3 for i in array do
在写代码中经常会遇到需要在数组循环中删除数组元素的情况,但删除会导致数组长度变化. package com.fortunedr.thirdReport; import java.util.ArrayList; import java.util.List; public class Test { public static void main(String[] args) { // TODO Auto-generated method stub List<String> list=new Arr