oracle sum()over函数的使用 over不能单独使用,要和分析函数:rank(),dense_rank(),row_number()等一起使用. over函数的参数:over(partition by columnname1 order by columnname2) 含义,按columname1指定的字段进行分组排序,或者说按字段columnname1的值进行分组排序. 例如:employees表中,有两个部门的记录:department_id =10和20 select depa
https://leetcode.com/problems/binary-tree-tilt/description/ 挺好的一个题目,审题不清的话很容易做错.主要是tilt of whole tree 的定义是sum of all node's tilt 而不是想当然的tilt of root. 一开是我就以为是简单的tilt of root 导致完全错误.思路其实可以看作是求sum of children 的变种,只是这里不仅要跟踪每个子树的sum 还要累计上他们的tilt. /** * D
纯板子.... 题意: 插入 xx 数 删除 xx 数(若有多个相同的数,因只删除一个) 查询 xx 数的排名(排名定义为比当前数小的数的个数 +1+1 .若有多个相同的数,因输出最小的排名) 查询排名为 xx 的数 求 xx 的前驱(前驱定义为小于 xx ,且最大的数) 求 xx 的后继(后继定义为大于 xx ,且最小的数) 然后... 然后就没有然后了.... 注意rotate... #include<cstdio> #include<iostream> #include<
using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { List<strudent> one = new List<strudent>(); on
Given an array which consists of non-negative integers and an integer m, you can split the array into m non-empty continuous subarrays. Write an algorithm to minimize the largest sum among these m subarrays. Note:Given m satisfies the following const
Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If there isn't one, return 0 instead. Example 1: Given nums = [1, -1, 5, -2, 3], k = 3, return 4. (because the subarray [1, -1, 5, -2] sums to 3 and is th
Given an integer array nums, find the sum of the elements between indices i and j (i ≤ j), inclusive. The update(i, val) function modifies nums by updating the element at index i to val. Example: Given nums = [1, 3, 5] sumRange(0, 2) -> 9 update(1, 2