The kth great number Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65768/65768 K (Java/Others)Total Submission(s): 6020    Accepted Submission(s): 2436 Problem Description Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round

Given an array of numbers, verify whether it is the correct preorder traversal sequence of a binary search tree. You may assume each number in the sequence is unique. Follow up: Could you do it using only constant space complexity? 这道题让给了我们一个一维数组,让我们

Given a binary search tree (BST), find the lowest common ancestor (LCA) of two given nodes in the BST. According to the definition of LCA on Wikipedia: “The lowest common ancestor is defined between two nodes v and w as the lowest node in T that has

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses

03-树1. List Leaves (25) Given a tree, you are supposed to list all the leaves in the order of top down, and left to right. Input Specification: Each input file contains one test case. For each case, the first line gives a positive integer N (<=10) wh

一个被广泛使用的面试题: 给定一个二叉搜索树,请找出其中的第K个大的结点. PS:我第一次在面试的时候被问到这个问题而且让我直接在白纸上写的时候,直接蒙圈了,因为没有刷题准备,所以就会有伤害.(面完的感慨是:千里马常有,伯乐不常有. 互联网公司普遍浮躁,想拿到互联网公司的入场券,我得回去刷题.) 知耻而后勇,于是我回家花了两个半小时(在不参考任何书本和网路上的源码的前提下),从构建BST开始,到实现中序遍历,最后用递归方法写出bst_findKthNode()并用gdb调试成功. 不过,使用递归

Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target. Example 1: Input: 5 / \ 3 6 / \ \ 2 4 7 Target = 9 Output: True Example 2: Input: 5 / \ 3 6 / \ \ 2 4

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST. Note: next() and hasNext() should run in average O(1) time and uses

Given the root node of a binary search tree, return the sum of values of all nodes with value between L and R (inclusive). The binary search tree is guaranteed to have unique values. Example 1: Input: root = [10,5,15,3,7,null,18], L = 7, R = 15 Outpu

面试题 63:二叉搜索树的第k个结点 题目:给定一颗二叉搜索树,请找出其中的第k大的结点.例如, 5 / \ 3 7 /\ /\ 2 4 6 8 (见下面的图1) 中,按结点数值大小顺序第三个结点的值为4. 图1:一个有7个结点的二叉搜索树,如果按结点数值大小顺序输出,则第3个结点的值是4 提交网址: http://www.nowcoder.com/practice/ef068f602dde4d28aab2b210e859150a?tpId=13&tqId=11215 分析: 对于二叉搜索树BS

Medium! 题目描述: 给定一个整数 n,求以 1 ... n 为节点组成的二叉搜索树有多少种? 示例: 输入: 3 输出: 5 解释: 给定 n = 3, 一共有 5 种不同结构的二叉搜索树: 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 解题思路: 这道题实际上是Catalan Number卡塔兰数的一个例子,如果对卡塔兰数不熟悉的童鞋可能真不太好做.先来看当 n = 1的情况,只能形成唯一的一棵二叉搜索树,n分别为1,2,3的情况如

A Binary Search Tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a node contains only nodes with keys less than or equal to the node's key. The right subtree of a node contains only nodes with

The lowest common ancestor (LCA) of two nodes U and V in a tree is the deepest node that has both U and V as descendants. A binary search tree (BST) is recursively defined as a binary tree which has the following properties: The left subtree of a nod

接着第三课的内容和讲了第四课的部分内容 1.介绍二叉搜索树 在二叉树上,何为一个节点的后继节点? 何为搜索二叉树? 如何实现搜索二叉树的查找?插入?删除? 二叉树的概念上衍生出的. 任何一个节点,左比他小,右比他大.标准搜索二叉树是没有重复值的. TreeMap就是搜索二叉树,key是有序组织起来的,组织方式是搜索二叉树,具体就是红黑树(具有某一种平衡性的搜索二叉树),和HashMap的无序分布不同. 有序的话,能完成更多的事情,找刚刚小的.刚刚大的. 查数很方便,如果左子树和右子树高度差不超过

[Leetcode] Unique binary search trees 唯一二叉搜索树 Unique Binary Search Trees leetcode java 描述 Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2

Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example,Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 题意:给定数n,二叉树的结点的值分别为1,2....n.问能组成多少种不同的二叉搜索树. 二叉

Given a binary tree, find the largest subtree which is a Binary Search Tree (BST), where largest means subtree with largest number of nodes in it. Note:A subtree must include all of its descendants.Here's an example: 10 / \ 5 15 / \ \ 1 8 7 The Large

一.题目 给定一颗二叉搜索树,请找出其中的第k大的结点.例如, 5 / \ 3 7 /\ /\ 2 4 6 8 中,按结点数值大小顺序第三个结点的值为4. 二.解法 package algorithm7; public class KthNode62 { public static void main(String[] args) { KthNode62 kth = new KthNode62(); TreeNode t1 = new TreeNode(5); TreeNode t2 = new

实现一个二叉搜索树迭代器.你将使用二叉搜索树的根节点初始化迭代器. 调用 next() 将返回二叉搜索树中的下一个最小的数. 示例: BSTIterator iterator = new BSTIterator(root); iterator.next(); // 返回 3 iterator.next(); // 返回 7 iterator.hasNext(); // 返回 true iterator.next(); // 返回 9 iterator.hasNext(); // 返回 true

Implement an iterator over a binary search tree (BST). Your iterator will be initialized with the root node of a BST. Calling next() will return the next smallest number in the BST Note: next() and hasNext() should run in average O(1) time and uses O

题目链接 https://leetcode.com/problems/binary-search-tree-iterator/description/ 题目描述 实现一个二叉搜索树迭代器.你将使用二叉搜索树的根节点初始化迭代器. 调用 next() 将返回二叉搜索树中的下一个最小的数. 注意: next() 和hasNext() 操作的时间复杂度是O(1),并使用 O(h) 内存,其中 h 是树的高度. 题解 代码 /** * Definition for binary tree * publi