第一种是一组json数据实现分页的效果,也就是每一次展示5条数据.第二种场景是每一秒展示4条数据,直到全部显示完.两种思路都做个笔记记录下. var nums = 5; //每页出现的数量 var pages = Math.ceil(data.length/nums); //得到总页数 var thisDate = function(curr){ //此处只是演示,实际场景通常是返回已经当前页已经分组好的数据 var str = '', last = curr*nums - 1; last =
方法1:临时表 * into #aa from table order by time-- 将top m笔插入 临时表 select * from #aa order by time desc --drop table #aa --删除临时表 方法2: * from ( * from table order by time asc) order by time desc 方法3: not in * from v_company where ( id not in ( id from v_comp
delete from TableName where id in( SELECT ID FROM(SELECT * FROM TableName t0WHERE(t0.Field1,t0.Field2) IN ( SELECT t1.Field1, t1.Field2 FROM TableName AS t1 GROUP BY t1.Field1, t1.Field2 HAVING count(*) > 1 )AND t0.ID NOT IN ( SELECT min(t2.ID) FROM
以下sql是a,b两张表通过关联条件id修改a表值,如果b表有重复数据记录,选第一条更新,红色条件为附加限制条件,具体视情况而定: UPDATE a SETname = b.fname,pwd = b.lnameFROM bWHERE a.id = b.id AND a.id in (2,3) 以下sql为查询单表中重复记录: select * from b t1 where t1.fname in (select t2.fname from b t2 group by t2.fname ha
最近面试中都遇到了这样一个数据库题: 删除表中的重复数据,有且只保留一条重复数据. 思路: 1)这个题需要用到rowid,首先找到重复数据的rowid,并找出rowid最大或最小值,作为删除的条件: select min(rowid) from aa group by Name having count(Name) > 1 2)根据name找出数量大于1的name select name from aa group by name having count(name) > 1 3)根据上两个条
Sightseeing Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 1023 Accepted Submission(s): 444 Problem Description Tour operator Your Personal Holiday organises guided bus trips across the Ben
<?php class czy { public $host="localhost"; //地址 public $uid="root"; //用户名 public $pwd="*******";//用户密码 public $dbname="*******";//用户数据库名 /** *给一个sql语句,返回执行的结果 *@param string @sql用户指定的sql语句 *@param int $type 用户给的
今天跟大家分享两条SQL语句,是关于查询某表中重复字段以及显示该字段的重复条数. 1.select * from 表名 where 列名 in (select 列名 from 表名 group by 列名 having COUNT(*)>1) order by 列名 运行结果: 注*将表中某列下所有重复的字段查询出来,如果想查询该列中重复条数>=n的话,只需将sql语句中的">1"改为"n-1"即可. 2.select 列名,count(*) CO