今天项目组的一个同事问我如何快速的找到一个Excel中第3列和第5列的值完全重复的值,我想了想虽然Excel中自带查找重复值的功能,但是好像只能对同一列进行比较,所以就写了一个VBA进行处理,VBA非常简单,但效果不错. Sub FindDuplicatesInColumn() Dim lastRow As Long Dim matchFoundIndex As Long Dim iCntr As Long lastRow = ' 初始化临时列, 第7列用来存放结果,第8列将3 5两列的值拼接起
mydict = {"key1":"value1", "key2":"value2"} 在Django模板中查找字典值的常规方法是{{mydict.key1}},{{mydict.key2}}.如果键是循环变量怎么办?即: {% for item in list %} # list中元素,都有一个NAME属性 {{ mydict.item.NAME }} # 取出字典中相对应的NAME属性的key对应的value {% end
import docx, os def readDocx(fileName): doc = docx.Document(fileName) content = '\n'.join([para.text for para in doc.paragraphs]) return content def main(rootdir, value): fileList = os.listdir(rootdir) for each in fileList: filePath = os.path.join(ro
function cc.exports.findValueByTbl(tbl,key)--递归方法,用于查找tbl中对应的键值 for k,v in pairs(tbl) do if k == key then if type(tbl[i])=="table" then--如果是table类型,递归查找 return findValueByTbl(v,key) else return v end end end end
Function findAndCopy(srcFile As String, destFile As String, cmdFile As String) Dim WSH As Object, wExec As Object, result Dim val, n Dim i As Integer Dim sFile As Object, Fso As Object Dim cmdStr As String Set WSH = CreateObject("WScript.Shell")
描述 http://poj.org/problem?id=3685 一个n*n的矩阵,(i,j)的值为i*i+100000*i+j*j-100000*j+i*j,求第m小的值. Matrix Time Limit: 6000MS Memory Limit: 65536K Total Submissions: 5980 Accepted: 1700 Description Given a N × N matrix A, whose element in the i-th row and j