一.前言 无论是FPGA应用开发还是数字IC设计,时序约束和静态时序分析(STA)都是十分重要的设计环节.在FPGA设计中,可以在综合后和实现后进行STA来查看设计是否能满足时序上的要求.本文阐述基本的时序约束和STA操作流程.内容主要来源于<Vivado从此开始>这本书,我只是知识的搬运工. 二.时序约束与XDC脚本 时序约束的目的就是告诉工具当前的时序状态,以让工具尽量优化时序并给出详细的分析报告.一般在行为仿真后.综合前即创建基本的时序约束.Vivado使用SDC基础上的XDC脚本以文本

题目链接: http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=GRL_1_B   Single Source Shortest Path (Negative Edges) Input An edge-weighted graph G (V, E) and the source r. |V| |E| r s0 t0 d0 s1 t1 d1 : s|E|−1 t|E|−1 d|E|−1 |V| is the number of vert

题目链接:https://vjudge.net/contest/148584#problem/A 题目大意: 解题思路:题目要求为:输出与已知序列的每一个元素的f(i)(f(i)的定义如题)相同的字典序最小的序列.稍微思考便知,其实就是叫我们求出原序列的f(i),这个很容易做到,只要在最长上升子序列的模板题上稍微做一些改动,记录下原序列每一个元素的f(i)即可.具体实现见代码. #include <bits/stdc++.h> using namespace std; ; int rise[N

<题目链接> 题目大意: 裸的DP最长上升子序列,给你一段序列,求其最长上升子序列的长度,n^2的dp朴素算法过不了,这里用的是nlogn的算法,用了二分查找. O(nlogn)算法 #include <cstdio> #include <cstring> #include <algorithm> using namespace std; ; int a[N],rise[N]; int main(){ int n;while(~scanf("%d&

一.mariadb yum install mariadb mariadb-server systemctl restart mariadb systemctl enable mariadb mysql_secure_installation  (初始化mysql) MariaDB [(none)]> set password=password('redhat');  (数据库登录后,修改mariadb数据密码) MariaDB [mysql]> create user dream@local

双11临近的我发现自己真的很穷很穷很穷(重要的问题说三遍)-- 贫穷催人上进.于是我就寻思着在空闲时间自己捣鼓一下钱生钱的游戏是怎么玩的,毕竟就算注定做韭菜也要做一根有知识有理想的韭菜. 第一个要玩的模型就是股票交易中的均线黄金交叉. 作为一个基础的韭菜一定听说过均线黄金交叉原则,也就是说当短期移动平均线向上突破长期移动平均线,表明趋势见涨,适合买入:相反地如果短期移动平均线向下突破长期移动平均线,表明趋势看跌,适合卖出. 那么这个韭菜们都知道的交易原则是不是真的能帮大家赚钱呢?下面我们以中国平

Education 教育 The rise of college 'Grade Forgiveness' /*the rise of -的增加*/大学等级宽恕现象的增加. Universities are letting students take classes over again---a consequence of the pressure schools feel to ensure their "customers" are satisfied. /*over again

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 74110    Accepted Submission(s): 27711 Problem Description Contest time again! How excited it is to see balloons floating aro

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 87647    Accepted Submission(s): 33130 Problem Description Contest time again! How excited it is to see balloons floating ar

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 104108    Accepted Submission(s): 40046 Problem Description Contest time again! How excited it is to see balloons floating ar

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 106421 Accepted Submission(s): 41214 Problem Description Contest time again! How excited it is to see balloons floating around.

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 58555 Accepted Submission(s): 21498 Problem Description Contest time again! How excited it is to see balloons floating around.

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 91684    Accepted Submission(s): 34910 Problem Description Contest time again! How excited it is to see balloons floating aro

Let the Balloon Rise Time Limit:1000MS  Memory Limit:65536K Total Submit:92 Accepted:58 Description Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popula

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 123800    Accepted Submission(s): 48826 Problem Description Contest time again! How excited it is to see balloons floating ar

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=1004 Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 90295    Accepted Submission(s): 34294 Problem Description Contest time a

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

Let the Balloon Rise Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 65536/32768K (Java/Other) Total Submission(s) : 150   Accepted Submission(s) : 63 Problem Description Contest time again! How excited it is to see balloons floating around. B

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1004 Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 90644    Accepted Submission(s): 34459 Problem Description Contest time a

w玻璃碎片.0共享 http://www.agildata.com/database-sharding/ The Rise of Database Sharding The concept of Database Sharding has been gaining popularity over the past several years, due to the enormous growth in transaction volume and size of business applica

Let the Balloon Rise Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is