题目描述: Given a non-empty 2D matrix matrix and an integer k, find the max sum of a rectangle in the matrix such that its sum is no larger than k. 解题思路: 根据题意,寻找二维数组中所有可以组成的矩形中面积不超过k的最大值,所以必须要求出可能组成的矩形的面积并与k比较求出最终结果.这里为了最终不超时,可以在一下方面进行优化: 1.设置一个数组比较当前列(或
近期在看dnsjava 源码的时候,不经意间发现一个自己没有想过的问题: HashMap 如何使用key去查找对应的value的,这个问题很难用语言描述的清楚,那就使用代码来进行说明吧! public class test { public static void main(String[] args) { a aa = new a(); b bb = new b(); Map<Object,Object> c = new HashMap<Object,Object>(); c.p
using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Dictionary<int, string> test = new Dictionary<int, string> { }; test.Add(,&
hashCode和equals方法是Object类的相关方法,而所有的类都是直接或间接的继承于Object类而存在的,为此,所有的类中都存在着hashCode和equals.通过翻看Object类的相关源码,发现其hashCode的实现方式如下: public native int hashCode(); 从中可以看出,hashCode的实现是一个本地方法,并且其返回了一个int型的值.很多人都认为在默认情况下,hashCode返回的就是对象的存储地址,事实上这样的看法是不全面的,确实有
Find the length of the longest substring T of a given string (consists of lowercase letters only) such that every character in T appears no less than k times. Example 1: Input: s = "aaabb", k = 3 Output: 3 The longest substring is "aaa"
Problem UVA1618-Weak Key Accept: 103 Submit: 588Time Limit: 3000 mSec Problem Description Cheolsoo is a cryptographer in ICPC(International Cryptographic Program Company). Recently, Cheolsoo developed a cryptographic algorithm called ACM(Advanced Cr
#遍历字典, 分别打印key, value, key:value emp = {'name':'Tom', 'age':20, 'salary' : 8800.00} for k in emp.keys(): print('key = {}'.format(k)) for v in emp.values(): print('values = {}'.format(v)) for v,k in emp.items(): print('{v}:{k}'.format(v = v, k = k)) 打
java8中谨慎使用实数作为HashMap的key! java8中一个hashCode()函数引发的血案java8中一个hashCode()函数引发的血案1.起因2.实数的hashCode()3.总结1.起因让我关注到这一点的起因是一道题:牛客网上的max-points-on-a-line (如果链接打不开可以直接搜索题目哦) 题目是这么描述的: Given n points on a 2D plane, find the maximum number of points that lie on