检查数组重复(一)let inputValue = this.positionGroupInput[groupId].inputValue; if (inputValue) { for (let positionGroup of this.lists) { if (positionGroup.id === groupId) { // 检查重复性 let isExist = false; for (let position of positionGroup.positions) { (positi
var arr = ["曹阳","曹阳","曹阳","张三","张三","张三","张三","张三",]; var temp = []; var obj = {}; var newArr = []; ; i < arr.length; i++) { var dt = arr[i]; if (obj[dt]) { obj[dt]++; } el
判断数组中是否有重复元素,最容易想到的方法是使用2重循环,逐个遍历,比较,但是这个是最慢,最笨的方法,百度得出了更好的方法. var ary = new Array("111","22","33","111"); var nary=ary.sort(); for(var i=0;i<ary.length;i++){ if (nary[i]==nary[i+1]){ alert("数组重复内容:"+na
1.如何判断数组元素是否存在重复项 1)定义测试数组 //定义测试的数组(1个没有重复元素,1个有重复元素) var arr1 = new Array("111","333","222","444"); var arr2 = new Array("aa","cc","bb","dd","bb"); 2) 判断数组元素重复的方法
方法一:正则 var ary = new Array("111","ff","222","aa","222"); alert(mm(ary)) // 验证重复元素,有重复返回true:否则返回false function mm(a) { return /(\x0f[^\x0f]+)\x0f[\s\S]*\1/.test("\x0f"+a.join("\x0f\x0f&qu
var arr=[1,3,5,7,9,9,10,10,11,12,34,3,6,92,1]; var tempbool = false; //默认无重复 for (let index = 0; index < arr.length; index++) { for (let i = index+1; i < arr.length; i++) { if ( arr[index]== arr[i] ) { tempbool = true; } } } if (tempbool) { console.
