二叉搜索树是常用的概念,它的定义如下: The left subtree of a node contains only nodes with keys less than the node's key. The right subtree of a node contains only nodes with keys greater than the node's key. Both the left and right subtrees must also be binary search
YII框架中可以使用foreach遍历对象以及可以使用数组形式直接访问对象的原因在YII框架的使用过程中,我们可以使用foreach直接遍历findAll等方法返回的对象的属性为什么呢?其实这与CModel实现的接口相关,接下来我们看下其实现的整个过程对于一个我们定义的model,它会继承虚类CActiveRecord,CActiveRecord类继承于CModel,如下所示: class special extends CActiveRecord { } abstract class CAct
很坑的一道题,读了半天才读懂题,手忙脚乱的写完(套上模板+修改模板),然后RE到死…… 题意: 题面上告诉了我们这是一棵二叉树,然后告诉了我们它的先序遍历,然后,没了……没了! 反复读题,终于在偶然间注意到了这一句——"Not only that, when numbering the rooms, they always number the room number from the east-most position to the west." 它告诉我们,东边的点总是比西边的点
JavaScript中的遍历: 1.for 遍历 var anArray = ['one','two']; for(var n = 0; n < anArray.length; n++) { //具体代码 } 2.for(var p in anObject)遍历 var anObject = {one: 1, two: 2}; for(var p in anObject) { //具体代码 } Jquery遍历: //数组遍历 var anArray = ['one','two'
Given preorder and inorder traversal of a tree, construct the binary tree. Note:You may assume that duplicates do not exist in the tree. For example, given preorder = [,,,,] inorder = [,,,,] Return the following binary tree: / \ / \ 前序.中序遍历得到二叉树,可以知道