在SQL SERVER中获取表中的第二条数据, 思路:先根据时间逆排序取出前2条数据作为一个临时表,再按顺时排序在临时表中取出第一条数据 sql语句如下: select top 1 * from(select top 2 * from NumberLog where UserName = '管理员' order by dateTime desc ) [table] order by dateTime asc
OLAP的12条准则 Multidimensional conceptual view OLAP模型必须提供多维概念视图 User-analysts would view an enterprise as being multidimensional in nature – for example, profits could be viewed by region, product, time period, or scenario (such as actual, budget, or fo
/*这里的1指的是获取一条数据,2指的是从第二条开始获取*/ [e:loop={"select * from phome_ecms_news where classid='2' limit 1,2",1,24,0}] /*下边这行代码只有在想获取详情的时候用到*/ <?php $fr=$empire->fetch1("select newstext from phome_ecms_news_data_{$bqr[stb]} where id='$bqr[id]'&
第二条 遇到多个构造器参数时,可以考虑用构建器 当遇到有多个构造器参数时,常见的是用重叠构造器,即: public class TestClass{ public TestClass(int para0){ this(para0,0); } public TestClass(int para0,int para1){ this(para0,para1,0); } public TestClass(int para0,int para1,int para2){ this.para0 = para0
1.把C++当成一门新的语言学习(和C没啥关系!真的.): 2.看<Thinking In C++>,不要看<C++变成死相>: 3.看<The C++ Programming Language>和<Inside The C++ Object Model>,不要因为他们很难而我们自己是初学者所以就不看: 4.不要被VC.BCB.BC.MC.TC等词汇所迷惑——他们都是集成开发环境,而我们要学的是一门语言: 5.不要放过任何一个看上去很简单的小编程问题——他们
创建用到的表的SQL CREATE TABLE [dbo].[emp_pay]( [employeeID] [int] NOT NULL, [base_pay] [money] NOT NULL, [commission] [decimal](2, 2) NOT NULL ) ON [PRIMARY] 生成的表,及表中的数据: --方法一 select top 1 * from ( SELECT TOP 2 * FROM [dbo].[emp_pay] WHERE base_pay = 50